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3 years ago

For each direct variation find the constant of variation. The find the value of y when x=-5

Mathematics

1 answer:

finlep [7]3 years ago

6 0

The constant of direct variation is 5 then
Y= -10 when X= -5

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PLEASE HELPPPP!

nirvana33 [79]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Trigonometric equations <br><br> 2sin(theta) + 3 = 4

max2010maxim [7]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve for x ~

$\qquad \sf \dashrightarrow \:2 \sin(x) + 3 = 4$

$\qquad \sf \dashrightarrow \:2 \sin(x) = 4 - 3$

$\qquad \sf \dashrightarrow \:2 \sin(x) = 1$

$\qquad \sf \dashrightarrow \:\sin(x) = \frac{1}{2}$

$\qquad \sf \dashrightarrow \:x = 30 \degree \: \: or \: \: \frac{\pi}{6} \: rad$

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6 0

2 years ago

PLZ HELP. ANSWER ALL OF THE QUESTIONS

Natalija [7]

The answer is C. 5 1/2 feet

6 0

3 years ago

Correct answer.

skad [1K]

Answer:

18 inches

Step-by-step explanation:

Given: The heights of both cylinders are 48 inches and 32 inches. Diameter of the larger cylinder is 12 inches

To find: diameter of the larger cylinder

Solution:

Height of the larger cylinder (H) = 48 inches

Height of the smaller cylinder (h) = 32 inches

Diameter of the smaller cylinder (d) = 12 inches

Radius of the smaller cylinder (r) = d/2 =12/ 2= 6 inches

As two cylinders are similar, their heights and radii are proportional.

$\frac{r}{h}=\frac{R}{H}\\\frac{6}{32}=\frac{R}{48}\\R=\frac{6}{32}\times 48=9\,\,inches$

Diameter of the larger cylinder = 2R = 2(9) = 18 inches

4 0

2 years ago

Two cars raced at a race track. the faster car traveled 20 mph faster than the slower car. in the time that the slower car trave

ruslelena [56]

If the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.

Given that the faster car is travelling 20 mph faster than slower car and when slower car travels 165 miles the faster car travels 225 miles.

We are required to find the speed of slower car and faster car.

let the speed of slower car be x mph.

In this way the speed of faster car be (x+20) mph.

Speed=Distance/ time

We have to first take slower car.

x=165/Time

Time=165/x-----------1

Now by taking faster car.

x+20=225/time

Time=225/(x+20)-------2

From equation 1 an equation 2.

165/x=225/(x+20)

225x=165x+3300

225x-165x=3300

60x=3300

x=55 mph

Faster car=55+20

=75 mph.

Hence if the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.

Learn more about speed at brainly.com/question/4931057

#SPJ1

5 0

1 year ago