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UNO [17]
3 years ago
10

What is the amplitude, period, and phase shift of y= 5cos( x/2 + 2pi/3)

Mathematics
1 answer:
nordsb [41]3 years ago
3 0
Y = A cos(Bx + C)
A - amplitude
\frac{2\pi}{B} - period
- \frac{C}{B} - phase shift

y=5\cos{( \frac{x}{2} + \frac{2\pi}{3} )}
\\
\\y=5\cos{( \frac{1}{2}x + \frac{2\pi}{3})}
\\
\\A=5,B= \frac{1}{2},C= \frac{2\pi}{3}

Amplitude: 5
Period: \frac{2\pi}{B}=\frac{2\pi}{\frac{1}{2}}=4\pi
Phase shift: - \frac{C}{B} =- \frac{\frac{2\pi}{3}}{\frac{1}{2}}= -\frac{4\pi}{3}
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Answer: 12√6

Step-by-step explanation:

Given the expression;

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3 years ago
Tan39= x/68<br> Plz help. Will give brainliet
lesya [120]

Answer:

\huge\boxed{x \approx 55}

Step-by-step explanation:

We need to note that this is an equation, in which we can solve for x.

tan(39) = \frac{x}{68}

We can use a calculator to find the tangent of 39 - we type 39 into the calculator then press the "TAN" button to find it's tangent. We find that to be around 0.81.

We now have the formula simplified down to 0.81 = \frac{x}{68}. To solve for x, we want to isolate it on one side, so we can multiply both sides by 68 to get rid of the fraction.

We know have 0.81 \cdot 68 = x

0.81 \cdot 68 = 55.08 \approx 55, so x is approximately 55.

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Answer: B) False

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