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marishachu [46]
3 years ago
5

a term in an arithmetic sequence is 488. the first term of the sequence is 7 and the common difference is 13. find the term numb

er.
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0

Answer: the term number is 38

Step-by-step explanation:

Let the number of the term be x

The value of the xth term = 488

In an arithmetic sequence, the terms differ by a common difference, d. This means that the difference between two consecutive terms, d is constant.

The formula for the nth term is

Tn = a + (n-1)d

Where

Tn = the nth term of the arithmetic sequence

a = the first term of the arithmetic sequence.

d = common difference.

From the information given,

a = 7

d = 13

We are looking for the xth term.

Tx = 488 = 7 + (x-1)13

488 = 7 + 13x - 13

Collecting like terms on the left hand side and right hand side of the equation,

13x = 488 -7 + 13

13x = 494

x = 38

The value of the 38th term is 488.

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Answer:

  A: -1, 3/5

  B: (-1/5, -3 1/5)

  2: plot the given points and draw a curve through them.

Step-by-step explanation:

<h3>Part A</h3>

The x-intercepts are most easily found from a graph of the function. I like the Desmos graphing calculator for this purpose. The x-intercepts are -1 and 3/5.

You can also find the x-intercepts by factoring the function.

  f(x) = 5x^2 +5x -3x -3 = 5x(x +1) -3(x +1) = (5x -3)(x +1)

The x-intercepts are the values of x that make the factors zero:

  5x -3 = 0   ⇒   x = 3/5

  x +1 = 0   ⇒   x = -1

__

<h3>Part B</h3>

The vertex is on the axis of symmetry, which is the vertical line at the value of x halfway between the zeros. (-1 +3/5)/2 = (-2/5)/2 = -1/5

The value of f(x) there is ...

  f(-1/5) = (5(-1/5) +2)(-1/5) -3 = (-1 +2)(-1/5) -3 = -1/5 -3 = -3 1/5

The vertex is (-1/5, -3 1/5).

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<h3>Part 2</h3>

The easiest step to take to graph the function is to type it into a graphing calculator (see attached).

If you're graphing this by hand, the three points given in parts A and B will be on the graph. The leading coefficient in the function is 3, so the x^2 parent function is vertically stretched by a factor of 3. This can make it a little more difficult to find points that lie on the graph.

Recognizing that the vertex form equation is ...

  f(x) = 3(x +1/5) -3 1/5

I might choose x-values that are -1/5 ± 1/2 to get y-values that are -3 1/5 + 3/4. And, x = -1/5 ± 1 ⇒ y = -3 1/5 +3.

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