Answer: 10.7 years.
Step-by-step explanation:
7,300 * (1 + 0.015)^x = 8,560 <=>
7,300 * 1.015^x = 8,560 <=>
1.015^x = 8,560 / 7,300 <=>
1.015^x = 1.1726 <=>
x = 10.694
To the nearest tenth:
x = 10.7 years
Answer:
Approximately 107years
Step-by-step explanation:
Given the population of Mathloversville modelled by the equation P=38e^0.095t where t is the number of years from now.
To find the time it will take the population to reach 1million from now, we will substitute P = 1,000,000 into the equation given
1,000,000 = 38e^0.095t
Dividing both sides by 38
1,000,000/38 = e^0.095t
Taking the ln of both sides
ln(1,000,000/38) = ln e^0.095t
ln26,315.79 = 0.095t
10.18 = 0.095t
t = 10.18/0.095
t = 107.16years
It will take approximately 107years for the population to reach 1million
3 ( x + 1) = 2 ( x + 11) Use the Distributive Property
3x + 3 = 2x + 22 Subtract 2x from both sides
x + 3 = 22 Subtract 3 from both sides
x = 19
X is equal to 8
Y is equal to 19
Write down the two numbers, one under the other, with the decimal points lined up.
Add zeros so the numbers have the same length.
Then subtract normally, remembering to put the decimal point in the answer.
