Answer:
Part A
HCOOH(aq) + NaOH(aq) → HCOONa(aq) + H2O(l)
Part B
ClCH2CH2CO2H(aq) + NaOH(aq) ------> ClCH2CH2CO2Na(aq) + H2O(l)
Explanation:
The reaction between an alkanoic acid and a base is a neutralization reaction. The reaction occurs as follows;
RCOOH + NaOH ----> RCOONa + H2O
We have to note the fact that the net ionic reaction still remains;
H^+(aq) + OH^-(aq) ---> H2O(l)
In both cases, the reaction can occur and they actually do occur as written.
Answer:
Yes, it erodes the limestone
Answer:
See explanation
Explanation:
Now the element sodium has electronic configuration of [Ne]3s1
Florine has an electronic configuration of [He] 2p5
We know that in the formation of sodium flouride, sodium looses one electron to form Na^+ while F gains one electron to form F^-. So the electronic configuration of both Na^+ and F^- now become; 1s2 2s2 2p6
