8.38e-21 Q^2 -1.07e-23 Q^2 +3.15e+19 Solve for Q
1 answer:
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<u>Answer:</u>
Balancing is making the number of atoms of each element same on both the sides (reactant and product side).
To find the number of atoms of each element we multiply coefficient × subscript
For example contains
5 × 1 = 5 ,Sr atoms and
5 × 2 = 10, Cl atoms
If there is a bracket in the chemical formula
For example we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )
So 3 × 3 = 9, Sr atoms
3 × 1 × 2 = 6, P atoms
3 × 4 × 2 = 24, O atoms are present.
Let us balance the equation
(Unbalanced)
Reactant Side # of atoms of each element Product Side
1 Fe 1
5 C 10
5 H 10
We see here C and H are not balanced on the reactant side so we multiply by 2 in order to get 10 that is, 2 times 5 =10 so now we have
Reactant Side # of atoms of each element Product Side
1 Fe 1
10 C 10
10 H 10
The Equation is Balanced !!!!! as there are same number of atoms of each element on both the sides.
Balanced!!!