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MAVERICK [17]
4 years ago
8

8.38e-21 Q^2 -1.07e-23 Q^2 +3.15e+19 Solve for Q

Chemistry
1 answer:
GarryVolchara [31]4 years ago
4 0
8.38e -21Q^2 -1.07e -23Q^2 +3.15e +19
= 10.46e -44Q^2 + 19
44Q^2 = 10.46e + 19
Q^2 = 523/2200e + 19/44
Q1= ≈ -1.03828
Q2= ≈ 1.03828
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Explanation:

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. Find the mass of 0.159 mol silicon dioxide.​
Juliette [100K]

Answer:

9.55 grams of SiO2

Explanation:

If the mass you mean by grams:

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Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:

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4 0
3 years ago
Consider the equilibrium reaction. 2 A + B − ⇀ ↽ − 4 C After multiplying the reaction by a factor of 2, what is the new equilibr
vredina [299]

Answer : The correct expression for equilibrium constant will be:

K_c=\frac{[C]^8}{[A]^4[B]^2}

Explanation :

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4A+2B\rightleftharpoons 8C

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4 0
3 years ago
1.72 moles of NOCI were placed in a 2.50 L reaction chamber
elena-14-01-66 [18.8K]

The equilibrium constant, Kc=0.026

<h3>Further explanation</h3>

Given

1.72 moles of NOCI

1.16 moles of NOCI  remained

2.50 L reaction chamber

Reaction

2NOCI(g) = 2NO(g) + Cl2(g).

Required

the equilibrium constant, Kc

Solution

ICE method

   2NOCI(g) = 2NO(g) + Cl2(g).

I    1.72

C   0.56           0.56         0.28

E   1.16              0.56         0.28

Molarity at equilibrium :

NOCl :

\tt \dfrac{1.16}{2.5}=0.464

NO :

\tt \dfrac{0.56}{2.5}=0.224

Cl2 :

\tt \dfrac{0.28}{2.5}=0.112

\tt Kc=\dfrac{[NO]^2[Cl_2]}{[NOCl]^2}\\\\Kc=\dfrac{0.224^2\times 0.112}{0.464^2}=0.026

4 0
3 years ago
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