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MAVERICK [17]
4 years ago
8

8.38e-21 Q^2 -1.07e-23 Q^2 +3.15e+19 Solve for Q

Chemistry
1 answer:
GarryVolchara [31]4 years ago
4 0
8.38e -21Q^2 -1.07e -23Q^2 +3.15e +19
= 10.46e -44Q^2 + 19
44Q^2 = 10.46e + 19
Q^2 = 523/2200e + 19/44
Q1= ≈ -1.03828
Q2= ≈ 1.03828
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2.50 x 2/1 = 5 mol of Citric Acid
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6 0
4 years ago
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An open flask sitting in a lab fridge looks empty, but it is filled with a mixture of gases called air. Calculate the number of
KATRIN_1 [288]

Answer: The number of molecules of gas the flask contains is 0.674\times 10^{23}

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm   (STP)

V = Volume of gas = 2.50 L

n = number of moles  = ?

R = gas constant =0.0821Latm/Kmol

T =temperature = 273K (STP)

n=\frac{PV}{RT}

n=\frac{1atm\times 2.50L}{0.0821 L atm/K mol\times 273K}=0.112moles

According to Avogadro's law:

1 mole of gas at STP contains =6.023\times 10^{23} molecules

Thus 0.112moles of gas at STP contains = \frac{6.023\times 10^{23}}{1}\times 0.112=0.674\times 10^{23} molecules

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7 0
3 years ago
Will the broom or vacuum have greater acceleration?
bekas [8.4K]

Answer:

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Explanation:

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3 years ago
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Arturiano [62]

Answer:

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Explanation:

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n =  \frac{N}{L} \\

where n is the number of moles

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L is the Avogadro's constant which is

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From the question

N = 1.204 × 10²⁴ atoms of gold

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n =  \frac{1.204 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>2 moles</h3>

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Explanation:

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