Answer:
2.1 kg of water
Explanation:
Step 1: Given data
- Moles of lithium bromide (solute): 4.3 moles
- Molality of the solution (m): 2.05 m (2.05 mol/kg)
- Mass of water (solvent): ?
Step 2: Calculate the mass of water required
Molality is equal to the moles of solute divided by the kilograms of solvent.
m = moles of solute/kilograms of solvent
kilograms of solvent = moles of solute/m
kilograms of solvent = 4.3 mol /(2.05 mol/kg) = 2.1 kg
1) Zn(CH₃COO)₂(s) + 2KOH(aq) = Zn(OH)₂(s) + 2CH₃COOK(aq)
Ksp{Zn(OH)₂}=1.2*10⁻¹⁷
2) Zn(CH₃COO)₂(s) + 2NaCN(aq) = Zn(CN)₂(s) + 2CH₃COONa(aq)
Ksp{Zn(CN)₂}=2.6*10⁻¹³
Ksp{Zn(OH)₂}<Ksp{Zn(CN)₂}
Zn(OH)₂ precipitates first
Explanation:
the pH of the solution defined as negatuve logarithm of ion concentration.
1. Hydrogen ion concentration when pH of the solution is 11.
..(1)
At pH = 11, the concentration of ions is .
2. Hydrogen ion concentration when the pH of the solution is 6.
..(2)
At pH = 6, the concentration of ions is .
3. On dividing (1) by (2).
The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is .
4. Difference between the ions at both pH:
This means that Hydrogen ions in a solution at pH = 7 has ions fewer than in a solution at a pH = 6
Answer:
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