Answer:
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Explanation:
From the question we are told that:
The Electric field of strength direction =Right
The Velocity of The First Electron=V_0
The Velocity of The Second Electron=V_0
Therefore

Generally, the equation for the Horizontal Displacement of electron is mathematically given by

Where
Acceleration is given as

And
Time

Therefore horizontal displacement towards the left is

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Answer:
143 kW
Explanation:
Given that
Diameter of the beam, d = 1 mm
Wavelength of the beam, λ = 193 nm
Time used by the pulse, t = 14 ns
Energy of the pulse, U = 2 mJ
Recall that Power can be mathematically calculated using the relation,
Power = Work Done / Time,
To solve this, we apply the formula
P = U / Δt
P = 2*10^-3 J / 14*10^-9 s
P = 142857 W
P = 143 kW
1. 2500/60 joules/sec
2. 2,500Nm
Answer:
In a velocity selector, there are two forces namely;
» Electric field Intensity
» Magnetic field density
<u>Relationship</u><u>:</u>

E is the electric field intensity
B is the magnetic flux density
Answer:
160N/m
Explanation:
According to Hooke's law which states that the extension of an elastic material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically,
F = ke where
F is the applied force
k is the spring constant
e is the extension
From the formula k = F/e
Since the body accelerates when the block is released, F = ma according to Newton's second law of motion.
The spring constant k = ma/e where
m is the mass of the block = 0.4kg
a is the acceleration = 8.0m/s²
e is the extension of the spring = 2.0cm = 0.02m
K = 0.4×8/0.02
K = 3.2/0.02
K = 160N/m
The spring constant of the spring is therefore 160N/m