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ELEN [110]
2 years ago
11

A woman pushes a 3.2kg textbook on a table as she walks forward 3.5 meters. How much work does the vertical component of the for

ce from her hand do on the textbook?in j
Physics
1 answer:
Effectus [21]2 years ago
4 0

Answer:

The done by the vertical component of force is zero.

Explanation:

Given data,

The mass of the textbook the women pushes horizontally, m = 3.2 kg

The displacement of the textbook, S = 3.5 m

Let the force of the women acts on the book horizontally,

Therefore, the horizontal component of force is maximum and the vertical component is zero.

If  F is the force applied by the women, then the horizontal and vertical component of the force is,

                                         F_{x}=F Cos\theta

                                         F_{y}=F Sin\theta

Since the force is acting along with the horizontal x component, the vertical component of the force is zero.

Hence, the done by the vertical component of force is zero.

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11) A man is on a 1/4 on a bridge. A train is coming the same direction he is going. The man can run across the bridge in the sa
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15mph

If the man turns and runs toward point A, he will cover

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If the man runs forward toward point B, what part of the bridge

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him 3/8 + 3/8 = 6/8 = 3/4 of the way across the bridge by the

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since we know that the man and the train will meet at B, this

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If it takes the man the same time to cover 1/4 of the bridge

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Since the train's speed is known to be 60 mph, this means that

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7 0
2 years ago
A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is
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The acceleration of the sled will be 1.30 m/s². Force is defined as the product of mass and acceleration.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Given data;

m(mass of sled)=8 kg

Θ is the inclination of force= 50°

Force of friction,f=2.4 N.

The applied force at the given angle is resolved into the two-component as;

\rm F_h=F cos \theta \\\\ F_h= 20 cos 50 ^0 \\\\ F_h= 12.85 \ N

\rm F_v=F sin \theta \\\\  F_v=20 sin 50^0 \\\\   F_v=15.32 \ N

The net vertical force is zero;

\rm F_N=mg-Fsin50^0 \\\\ \rm F_N=8 \times 9.81 -15.32 \\\\ F_N=63.1 \ N \\\\

From Newton's second law the net force as;

\rm \sum F_{net}=ma \\\\ Fcos 60^0-f =ma \\\\ a=\frac{12.855-2.4}{8} \\\\a = 1.30 \ m/s^2

Hence, the acceleration of the sled will be 1.30 m/s².

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5 0
1 year ago
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Seismic reflectivity is the bouncing back of seismic waves at a boundary of geological layers due to different densities or subsurface formation. This is especially true for secondary waves that are unable to pass through liquid layers of the earth like the outer core and mantle. When they reach the boundary of these layers they bounce back towards the earth's surface.

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