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ELEN [110]
3 years ago
11

A woman pushes a 3.2kg textbook on a table as she walks forward 3.5 meters. How much work does the vertical component of the for

ce from her hand do on the textbook?in j
Physics
1 answer:
Effectus [21]3 years ago
4 0

Answer:

The done by the vertical component of force is zero.

Explanation:

Given data,

The mass of the textbook the women pushes horizontally, m = 3.2 kg

The displacement of the textbook, S = 3.5 m

Let the force of the women acts on the book horizontally,

Therefore, the horizontal component of force is maximum and the vertical component is zero.

If  F is the force applied by the women, then the horizontal and vertical component of the force is,

                                         F_{x}=F Cos\theta

                                         F_{y}=F Sin\theta

Since the force is acting along with the horizontal x component, the vertical component of the force is zero.

Hence, the done by the vertical component of force is zero.

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We have that the spring constant is mathematically given as

k=2.37*10^{11}N/m

Generally, the equation for angular velocity is mathematically given by

\omega=\sqrt{k}{m}

Where

k=spring constant

And

\omega =\frac{2\pi}{T}

Therefore

\frac{2\pi}{T}=\sqrt{k}{n}

Hence giving spring constant k

k=m((\frac{2 \pi}{T})^2

Generally

Mass of earth m=5.97*10^{24}

Period for on complete resolution of Earth around the Sun

T=365 days

T=365*24*3600

Therefore

k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2

k=2.37*10^{11}N/m

In conclusion

The effective spring constant of this simple harmonic motion is

k=2.37*10^{11}N/m

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3 years ago
Which is not a correct way to measure wavelength?
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3 years ago
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) A striker can give the ball an initial speed of 30m/s. Within what two elevation angles must he kick
sveticcg [70]

Answer:

  about 19.6° and 73.2°

Explanation:

The equation for ballistic motion in Cartesian coordinates for some launch angle α can be written ...

  y = -4.9(x/s·sec(α))² +x·tan(α)

where s is the launch speed in meters per second.

We want y=2.44 for x=50, so this resolves to a quadratic equation in tan(α):

  -13.6111·tan(α)² +50·tan(α) -16.0511 = 0

This has solutions ...

  tan(α) = 0.355408 or 3.31806

The corresponding angles are ...

  α = 19.5656° or 73.2282°

The elevation angle must lie between 19.6° and 73.2° for the ball to score a goal.

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I find it convenient to use a graphing calculator to find solutions for problems of this sort. In the attachment, we have used x as the angle in degrees, and written the function so that x-intercepts are the solutions.

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makvit [3.9K]
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4 years ago
When will you say a body is in a) uniform acceleration (b) non uniform acceleration
s2008m [1.1K]

Answer:

See below ~

Explanation:

Part (a) :

We can say a body is in uniform acceleration if the acceleration of the object remains constant with respect to time throughout its motion.

Part (b) :

We can say a body is non-uniform acceleration if the acceleration of the body varies with respect to time throughout its motion.

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