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Alex Ar [27]
3 years ago
14

[sorry im doing this again] When does an electrically charged object attract another object?

Physics
1 answer:
mojhsa [17]3 years ago
8 0
B Since when each object is negatively charged it becomes a electronic. Basically
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A first-order reaction has a rate constant of 0.241/min. if the initial concentration of a is 0.859 m, what is the concentration
nordsb [41]

Answer: 0.077 M

Explanation:

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant = 0.241minute^{-1}

t = time taken for decay process = 10 minutes

a = initial amount of the reactant= 0.859 M

a - x = amount left after decay process =?

Putting values in above equation, we get:

0.241 minutes^{-1}=\frac{2.303}{10.0}\log\frac{0.859}{a-x}

(a-x)=0.077M

Thus the concentration of a after 10.0 minutes is 0.077 M.


5 0
3 years ago
Read 2 more answers
What is the potential energy of a puppy that weighs 18 N istting in a high chair 2 m high?
kykrilka [37]

Answer:

Potential energy =mass* acceleration due to gravity * height

mass*acceleration due to gravity =weight

hence potential energy of the puppy= weight * height

=18*2

=36 joule

6 0
3 years ago
What are power tools​
butalik [34]

Answer:

Tools that require electricty like drills

Explanation:

8 0
3 years ago
Read 2 more answers
Estimate the mass of the Great Pyramid of Giza, in tons. You make may use of the following information: the Great Pyramid is in
postnew [5]

Answer:

6005803.83105 short tons

Explanation:

The definition of density is \rho = \frac{m}{V}, and the volume of a pyramid is (confusingly written on the proposal) V=\frac{1}{3} Ah, so we can write:

m=\rho V=\rho V \frac{1}{3} Ah=\rho V \frac{1}{3} s^2h

Where s is the side of the base, being s^2 the area of that square.

We will write everything in S.I., and the best way to convert units is using conversion factors, for example, since 1m=100cm, we know that \frac{1m}{100cm}=1, and we can use this factor to convert anything written in cm to anything written in m. Example:

500cm=500cm\frac{1m}{100cm}=5m

Here we just multiplied 500cm by something that is equal to 1 (as every conversion factor must), so <em>it's not doing anything but changing the units</em>.

We can use this tool like this:

2.1\frac{g}{cm^3}=2.1\frac{g}{cm^3}(\frac{1Kg}{1000g})(\frac{100cm}{1m})^3=2100Kg/m^3

Where we have used the fact that 1^3=1 (<u>we can elevate any conversion factor to any number and they still will be 1</u>) and where we have placed strategically what is the numerator and what in the denominator so the units we don't want cancel out and the units we want appear.

Substituting then our values:

m=\rho V \frac{1}{3} s^2h=(2100Kg/m^3)\frac{1}{3} (230.34m)^2(146.7m)=5448373586.96Kg

And now we will convert to short tons using two conversion factors at the same time:

m=5448373586.96\ Kg(\frac{1\ lb}{0.45359237\ Kg})(\frac{1\ short\ ton}{2000\ lb} )=6005803.83105\ short \ tons

Remember, their value is 1, and we place the units to cancel the ones we don't want and keep the ones we want, here Kg cancel out, and lb cancel out, leaving the short tones.

8 0
3 years ago
Give an example of a Claim.
Olin [163]

Answer:

Yeah

Explanation:

Look at the pic!!

5 0
3 years ago
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