Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
Answer:
Acceleration up the ramp = -2.745 m/
Explanation:
Given
box is pulled at angle Θ = 
Force applied F = 185N
coefficient of friction, μ
= 0.27
mass of the box m = 35 kg
We know that,
acceleration due to gravity g = 9.8 m/
horizontal component
= F cosΘ = 185 * cos
=167.67
vertical component
= F sinΘ =185*sin
= 78.18
Another vertical component is due to gravity
, force in given by
= mg
= 35 x 9.8
= 343.35 N
Normal force
=
- 
= 343.35 - 78.18
= 265.17 N
Frictional force
=
* μ
= 265.17 * 0.27
= 71.596 N
To find acceleration, we know that,
force = mass x acceleration
acceleration = 
Here force is the summation of frictional force and horizontal component of the applied force. These force act in opposite directions.
force =
- 
= 71.596 - 167.67
= -96.074
acceleration = 
= -2.745 m/
Answer:
Power output = 
Explanation:
Given:
Mass of the elevator is, 
Height to which it is raised is, 
Acceleration due to gravity is, 
Time taken by the motor to raise the elevator is, 
Now, work done on the elevator by the motor is equal to the increase in the gravitational potential energy of the elevator.
Increase in gravitational potential energy is given as:

Therefore, work done by motor is, 
Now, we know that, power is work done in unit time. So, power output is given as:
![Power=\frac{W}{t}\\\\Power=\frac{10\times 10^4\ J}{5.0\ s}\\\\Power=2\times 10^4\ J/s\\\\Power=2\times 10^4\ W..........[1 W = 1\ J/s]](https://tex.z-dn.net/?f=Power%3D%5Cfrac%7BW%7D%7Bt%7D%5C%5C%5C%5CPower%3D%5Cfrac%7B10%5Ctimes%2010%5E4%5C%20J%7D%7B5.0%5C%20s%7D%5C%5C%5C%5CPower%3D2%5Ctimes%2010%5E4%5C%20J%2Fs%5C%5C%5C%5CPower%3D2%5Ctimes%2010%5E4%5C%20W..........%5B1%20W%20%3D%201%5C%20J%2Fs%5D)
Therefore, the power output of the first motor is 
Badminton is played to a score of 21 points
Answer:
plane LA534 will have to decrease it speed by twice that of plane LA639.
Explanation:
Since both planes want to land there must be a decrease in speed.
We are told that plane LA534 velocity is twice that of plane LA639.
Now for the two planes to land without a crash. the opposite or reverse will be the case in terms of deceleration, that is
Plane LA639 will have to decrease its speed by twice the decrease in speed of plane LA534