3 years ago

Please help on this one?

Physics

1 answer:

Setler79 [48]3 years ago

8 0

I may be wrong but I think the answer is open. Hope this helps.

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A car of mass m goes around a banked curve of radius r with speed v. If the road is frictionless due to ice, the car can still n

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Answer:

horizontal component of normal force is equal to the centripetal force on the car

Explanation:

As the car is moving with uniform speed in circle then the force required to move in the circle is towards the center of the circle

This force is due to friction force when car is moving in circle with uniform speed

Now it is given that car is moving on the ice surface such that the friction force is zero now

so here we can say that centripetal force is due to component of the normal force which is due to banked road

Now we have

$N sin\theta = \frac{mv^2}{R}$

$N cos\theta = mg$

so we have

$v = \sqrt{Rg tan\theta}$

so this is horizontal component of normal force is equal to the centripetal force on the car

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