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3 years ago

-0.4(0.5z + 4) = 3.2 What is the answer for this

2 answers:

8 0

-0.2z-1.6=3.2 you distribute the -0.4 to 0.5z and 4 and you get the equation above and then you add 1.6 to the other side and get
-0.2z=4.8 you divide both sides by -0.2 and you get z=-5

netineya [11]3 years ago

6 0

Answer:

z = - 24

Step-by-step explanation:

Given

- 0.4(0.5z + 4) = 3.2 ( divide both sides by the multiplier - 0.4 )

0.5z + 4 = - 8 ( subtract 4 from both sides )

0.5z = - 12 ( divide both sides by 0.5 )

z = - 24

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Hello someone please help !! Will mark brainliest

Elanso [62]

Answer:

a) domain: (0, ∞)

b) range: (-∞, ∞)

c) increasing everywhere

d) concave downward

Step-by-step explanation:

a) Your knowledge of the log function tells you it is defined for positive arguments. 9x > 0 means x > 0. The domain is all positive real numbers.

b) Your knowledge of the log function tells you it has output values ranging from -∞ to +∞. The range is all real numbers.

c) The function is monotonically increasing.

d) Since the output does not increase as fast as the input (the first derivative is decreasing), the function is concave downward.

8 0

3 years ago

Consider a normal distribution with mean 30 and standard deviation 2. What is the probability that a value selected at random fr

blagie [28]

The probability that the value selected at random is greater than 30 will be found as follows:
z-score is given by:
z=(x-mu)/sig
z=(30-30)/2=0
thus
P(x>30)=1-P(X<30)=1-P(z<0)=1-0.5=0.5
Answer P(x>30)=0.5

4 0

3 years ago

Find the distance between each pair of points. Round your answer to the nearest tenth. (-6, -5) and (2, 0)

Anna71 [15]

Answer:

The answer is

<h2>9.4 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-6, -5) and (2, 0)

The distance between them is

$d = \sqrt{ ({ - 6 - 2})^{2} + ({ - 5 - 0})^{2} } \\ = \sqrt{ ({ - 8})^{2} + ( { - 5})^{2} } \\ = \sqrt{64 + 25} \\ = \sqrt{89} \: \: \: \: \: \: \: \: \: \: \\ = 9.4339811$

We have the final answer as

<h3>9.4 units to the nearest tenth</h3>

Hope this helps you

7 0

3 years ago

Please help!! im on a timer!

frutty [35]

Answer:

The correct option is A

A) -10 ≤ x ≤ 10 , -10 ≤ y ≤ 10

Step-by-step explanation:

We have been given a system of equation:

y = -13x + 17

y = 5x - 23

We have to determine the best window range from the following options:

A) -10 ≤ x ≤ 10 , -10 ≤ y ≤ 10

B) -20 ≤ x ≤ 0 , -20 ≤ y ≤ 0

C) 0 ≤ x ≤ 20, 0 ≤ y ≤ 20

D) 20 ≤ x ≤ 40 , 20 ≤ y ≤ 40

The graph of both the equation is attached below, we can see that the graph shows the solution at the point (2.222, -11.869), where x is positive and y is negative

Now consider the options

Option A includes the solution

Option B doesn't show positive values for x

Option C doesn't show negative values for y

Option D doesn't include the x or y part of the solution

5 0

3 years ago

Solve the equation. dy dx = ay + b cy + d , where a, b, c, and d are constants. (assume a ≠ 0 and ay + b ≠ 0.)

Reil [10]

It solves it in x. the solution for y includes heavy use of the product log function.

dy/dx = ay + b/cy +d

(cy +d/ ay + b) dy = dx

∫ (cy +d/ ay + b) dy = x (t) + C

Into solving the integral, integration by parts followed by u substitution and another integration by parts.

∫ (cy +d/ ay + b) dy

u = cy + d dv = dy/ay + b

du = c dy v = ln I ay + b l / a

Then, use u substitution for the new integral

u = ay + b

du = a dy

∫ ln l ay + b I dy = ∫ ln IuI /a du = 1/a ∫ ln luI du

Integrating the natural log includes thus far another integration by parts

r = ln IuI ds = du

dr = du / u (s) = du

∫ ln IuI / du = u ln IuI - ∫ du = u ln IuI - ∫ a dy = (ay + b) ln Iay +bl – ay

The original integral of expression

∫ (cy +d/ ay + b) dy = cy + d/a ln lay+bl – c/a² [(ay+b) ln lay+bl – ay]

Then simplify

∫ (cy +d/ ay + b) dy = cy + d/a ln lay+bl – c/a²[(ay+b) ln lay+bl – ay]

= a (cy + d)/a² ln lay+bl – c (ay+b)/ a²ln lay+bl + c/a² ay

= cay + ad – cay – cb/ a² ln lay+bl + cay/a²

= ad – cb/a²ln lay+bl + cy/a

The final answer will be

x(t) + C = ad – cb/a² ln lay+bl + cy/a

x(t) = ad – cb/a² ln lay+bl + cy/a + k

3 0

3 years ago