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Galina-37 [17]
3 years ago
5

Catherine has $54. She plans to spend more than $20 of the money for a painting canvas. The rest will go toward paints. Each tub

e of paint costs $8.50. Assume that x represents the number of tubes of paint Catherine can buy
The inequality that represents this scenario is
1. 8.5x +20>54
2. 8.5x-20<54
3. 54-8.5x<20
4. 54- 8.5x>20
Mathematics
2 answers:
kakasveta [241]3 years ago
8 0

Answer:

4. 54- 8.5x>20

Step-by-step explanation:

Catherine only has $54, so she cannot spend more than that.

The canvas will cost at least $20, but we don't know how much exactly.

The tubes cost $8.50 each.

So, she starts with a total budget of $54, out of which she will buy paints (8.5x) and she wants to have at least $20 left for canvas.

So, we transpose those facts into the inequity:

54 - 8.5x > 20

s344n2d4d5 [400]3 years ago
8 0

Answer:

Opcion 4

54- 8.5x>20

Step-by-step explanation:

We must identify the quantities.

<u><em>Painting canvas </em></u>

more than $ 20

<u><em>Paint tubes (x): </em></u>

$ 8.50 per tube = 8.50x

<u><em>Available money: </em></u>

$ 54

Then the expenses must not exceed $ 54, and the budget for the painting canvas must be greater than $ 20

The money after buying the paint tubes is:

54-8.50x

We know that this amount must be greater than $ 20 because you need to buy the painting canvas. So  the inequality is:

54-8.50x> 20

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The line plot shows the number of letters in the last name of 12 children.
Ainat [17]

Answer:

The mode is 9 letters: True

The median is 7.5 letters: True

The mean is 7 letters: False

The graph is skewed right with an outlier of 2: False

Step-by-step explanation:

1) The mode is 9 letters. (True)

The mode is the value that shows up the most. 9 letters shows up the most as the length of a child's last name.

2) The median is 7.5 letters. (True)

The median is one of the middle points of a data set. This can be found by writing out all of the results from least to greatest, and crossing out each number starting from the ends.

2, 6, 6, 7, 7, 7, 8, 8, 9, 9, 9, 9

Once you meet in the middle, you should be left with 7 and 8. In this case, we find the mean of the two numbers, which is 7.5. (In cases where the data set has an odd amount - if there were 13 children instead of 12), you'd just use the middle piece of data.

3) The mean is 7 letters. (False)

The mean is also a middle point of a data set. However, this one is different. The mean can be found by adding up all of the numbers in the data set (2+6+6+7+7+7+8+8+9+9+9+9) and then dividing that number by the amount of numbers are in the data set. Setting this up as an expression would look like: \frac{2+6+6+7+7+7+8+8+9+9+9+9}{12}. By plugging this into a calculator you'd get 7.25 instead of just 7.

4) The graph is skewed right with an outlier of 2.

Although the outlier of 2 part of the statement is correct, the graph is not skewed right; it is skewed left.

5 0
2 years ago
I need help I don’t understand
kozerog [31]
You answer for a. show be 200+600-1 should e lil tj
8 0
3 years ago
What is the mode for the following set of data? 5,7,8,10,12,12
Volgvan

Answer:

12

Step-by-step explanation:

its the most common number

4 0
3 years ago
Read 2 more answers
Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road-oriented at an angle of 25
kap26 [50]

Answer:

6.31 mi

Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

a^2 = b^2 + c^2 - 2bc[cos(A)]

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi

The straight-line distance between the starting point and the end of the race is 6.31 mi

4 0
3 years ago
Gage's math teacher entered the seventh-grade student in a math competition. There was an enrollment fee of $30 and also $11 cha
Amanda [17]

Answer:

110 test

Step-by-step explanation:

Let

x ----> the number  of packet of 10 test

y ----> the total cost

we know that

The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151

so

The linear equation that represent this scenario is

y=11x+30

we have

y=\$151

substitute

151=11x+30

Solve for x

subtract 30 both sides

11x=151-30

11x=121

Divide by 11 both sides

x=11

The number of packets purchase was 11

To find out the number of test, multiply the number of packets by 10

11(10)=110\ test

4 0
3 years ago
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