Let's assume that the faster car has a 2 mile "head start".
The faster car is 1.2 times faster (48/40) than the slower car.
It will take five 2 mile trips to "catch" the other car.
Five 2 mile trips will take 5 * 40 seconds = 200 seconds.
Answer:
32
Step-by-step explanation:
Assuming ya mean

take derivitive
remember dy/dx e^x=e^x
also the chain rule
so

find where it equals 0


multiply both sides by e^x

divide both sides by 8

take ln of both sides


divide both sides by 9

x≈-1/5
f'(-1)<0
f'(0)>0
so it is increasing from x to infinity
the interval it is increasing on is