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4 years ago

Simplify -6²/ 12 - 2(-7)

Mathematics

1 answer:

Rasek [7]4 years ago

6 0

The simplify is 11, -6²/ 12 - 2(-7)=11

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A triangle has side lengths of 13, 9, and 5. Is the triangle a right triangle? Explain.

valentina_108 [34]

Answer: This triangle is not a right triangle

Step-by-step explanation:

In a right triangle, the hypotenuse(c) is always the longest side and a and b are the shorter sides. Thus, 5^2+9^2=13^2. Simplify this to get 25+81=169, then 106=169. Because 106 does not equal 169, it is not a right triangle.

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3 years ago

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Which benchmark fractions are less than 1 and greater than 1.

netineya [11]

1,4,and5 are greater than 1
2 and 3 are less than 1

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3 years ago

Tyyy uwu Find the area:

marysya [2.9K]

Answer:

152 cm²

Step-by-step explanation:

area of rectangle A+rectangle B

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3 years ago

Square root of 100/121

klasskru [66]

Ah... good ol' square roots...

Whenever you take the square root of multiplication or division, you can do the square roots separately. So, we can write:

$\sqrt{\frac{100}{121}} = \frac{\sqrt{100}}{\sqrt{121}}$

This nifty truth allows us to easily find the answer:
$\frac{\sqrt{100}}{\sqrt{121}} = \frac{10}{11}$

All done!

7 0

4 years ago

Public opinion in the large city of Bedrock is that 60 percent of the residents are in favor of increasing taxes to fund alterna

uysha [10]

Answer: 0.8461

Step-by-step explanation:

Let p be the proportion of residents are against the increase of taxes to fund alternatives to drug addiction treatment.

As per given , we have p=0.40

A random sample is taken with size : n= 400

Expecting sample proportion : $\hat{p}=\dfrac{150}{400}=0.375$

Now , the probability that more than 150 of the residents surveyed will be against increasing taxes if a random sample of 400 residents are surveyed will be :

$P(p>0.375)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.375-0.40}{\sqrt{\dfrac{0.40(0.60)}{400}}})$

$=P(z>\dfrac{0.375-0.40}{\sqrt{\dfrac{0.40(0.60)}{400}}})\ \ [\because\ z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]$

$=P(z>-1.02)=P(z-z)=P(Z$

$\approx0.8461$ [By z-table]

Hence, the approximate probability that more than 150 of the residents surveyed will be against increasing taxes if a random sample of 400 residents are surveyed is 0.8461 .

4 0

4 years ago

Simplify -6²/ 12 - 2(-7)​

Simplify -6²/ 12 - 2(-7)