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4 years ago

How do u solve y pluse 4 pluse 3(y pluse 2)

Mathematics

2 answers:

larisa86 [58]4 years ago

8 0

$y+4+3(y+2)$

$y+4+3y+6$

$y+3y+6+4$

$Answer:4y+10$

lesya [120]4 years ago

3 0

Y + 4 + 3(y+2) first distribute the 3
y + 4 + 3y + 6 then add like terms
4y + 10

therefore your answer should be 4y + 10

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A used automobile dealership recently reduced the price of a used compact car by 6%. If the price of the car before discount was

Alchen [17]

Answer:

The discount = $1,128

New price = $17,672

Step-by-step explanation:

Price of car before discount = $18,800

Discount given = 6% of price of car

Discount value in dollars = 6% of $18,800 = 6/100*$18,800 = $1,128

Thus, the discount is $1,128

New price = Price of car before discount - discount = $18,800- $1,128

New price = $17,672

7 0

3 years ago

Please please answer

gizmo_the_mogwai [7]

Answer:

$-5$

Step-by-step explanation:

$(f\circ g)(-1)=f(g(-1))=f(1-3)=f(-2)=-4-1=-5$

7 0

3 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$