Answer:
I think it is a
Step-by-step explanation:
Answer:
(2,20)
Step-by-step explanation:
The given function is

To see which point is not on this curve, we must substitute the points to see which does not satisfy the equation;
For the first point we substitute x=3 and f(x)=250

This is true.
For the second point (2,20), we put x=2 and y=20 to get:

This is false, hence (2,20) does not lie on this curve.
For (1,10), we have:

This is also true
Finally for (2,50), we have;

This is also true.
I dont really know. you dont know how big the walls are and how far 1 gallon goes so figure how far 1 gallon goes and then divide it by the 1,162.5
Answer:

Step-by-step explanation:
Let the equation of the line be
where, 'm' is its slope and
is a point on it.
Given:
The equation of a known line is:

A point on the unknown line is:

Both the lines are perpendicular to each other.
Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is 
When two lines are perpendicular, the product of their slopes is equal to -1.
Therefore,

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

The equation of a line perpendicular to the given line and passing through (4, -6) is
.