Ask question

Ask question

All categories

3 years ago

15

Classifying shapes what shape is this

2 answers:

ExtremeBDS [4]3 years ago

5 0

Answer:

its a right trapezoid. A right trapezoid is a trapezoid that has at least two right angles

Step-by-step explanation:

Anika [276]3 years ago

5 0

Answer:

this shape is a right trapezoid

Step-by-step explanation:

Its a trapezoid but with a right angle

You might be interested in

For the graph shown to the right, find (a) AB to the nearest tenth and (b) the coordinates of the midpoint of AB.

Shkiper50 [21]

AB =

$\sqrt{( {4 - (- 2))}^{2} + {( - 5 + 3)}^{2} } = \sqrt{40} = 6.3$
The midpoint os segment AB =

$(( \frac{ - 2 + 4}{2} ) = the \: x \: coordinate \: of \: the \: midpoint \\ \\ ( \frac{ - 3 - 5}{2})) = the \: y \: coordinate \: of \: the \: midpoint$
The midpoint is:

(1,-4)

8 0

3 years ago

Write two addition equations that each have a sum of -21.5

blondinia [14]

Answer:

-8.5 + -13 = -21.5

and

-15.5 + -6 = -21.5

6 0

3 years ago

Hbxhsnnsgdhejeebejhebejejrj

-Dominant- [34]

Answer:

?what?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

F(x) = 3x3<br> 3.3 – 2.02 + 4x - 5<br> g(x) = 6x - 7<br> Find (f + g)(x).

Andreas93 [3]

Answer:

C) (f+g)(x)= <em>3</em><em>x</em><em>^</em><em>3</em><em>-</em><em>2</em><em>x</em><em>^</em><em>2</em><em>+</em><em>1</em><em>0</em><em>x</em><em>-</em><em>1</em><em>2</em>

3 0

3 years ago

The number of <img src="https://tex.z-dn.net/?f=x" id="TexFormula1" title="x" alt="x" align="absmiddle" class="latex-formula"> s

Alex777 [14]

Answer:

D. 4

Step-by-step explanation:

Without actually solving the equation, recall that for $a=|b|$ , there are two cases:

$\begin{cases}a=b, \\a=-b\end{cases}$

In the given equation $|x-2|^{10x^2-1}=|x-2|^{3x}$ , there are two pairs of absolute value symbols.

Since each has two cases, there must be a total of $2\cdot 2=\boxed{4}$ different equations created.

All four cases are:

$\begin{cases}(x-2)^{10x^2-1}=(x-2)^{3x},\\(-x+2)^{10x^2-1}=(x-2)^{3x},\\(x-2)^{10x^2-1}=(-x+2)^{3x},\\(-x+2)^{10x^2-1}=(-x+2)^{3x}\end{cases}$

Exponents differ, hence clearly there are four possible solutions to this equation.

You can solve for all four values of $x$ by taking the log of both sides and using a bit of algebra to verify you have four solutions.

5 0

3 years ago