Answer:
Step-by-step explanation:
3(4a + 6b) = 3*4a + 3*6b = 12a + 18b
-2(7a + b) = -2*7a + (-2)*b = -14a - 2b
![\frac{5[3(4a+6b)-2(7a+b)-b]}{20}=\frac{5[12a+18b-14a-2b-b]}{20}\\\\ \frac{5[-2a+15b]}{20}=\frac{15b-2a}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%5B3%284a%2B6b%29-2%287a%2Bb%29-b%5D%7D%7B20%7D%3D%5Cfrac%7B5%5B12a%2B18b-14a-2b-b%5D%7D%7B20%7D%5C%5C%5C%5C%20%5Cfrac%7B5%5B-2a%2B15b%5D%7D%7B20%7D%3D%5Cfrac%7B15b-2a%7D%7B4%7D)
x =1/4
The K value is often found at the end of the formula for instance, f(x) = log(x) +k. The K value moves the graph up or down depending on if it is negative or positive.
Answer:
7.65 meters.
Step-by-step explanation:
Let x represent the distance that diver will travel.
We have been given that a scuba diver is exploring at an elevation of -12.2 meters. As the diver rises to the surface, she plans to stop and rest briefly at a reef that has an elevation of -4.55 meters. We are asked to find the distance that diver will travel.
The initial elevation plus x will be equal to -4.55 meters. We can represent our given information in an equation as:



Therefore, the scuba diver will travel a vertical distance of 7.65 meters.
The area of a kite is (1/2) * x * y, where x and y are the length of the two diagonals. In this case, the length of the two diagonals are 10 ft and 2 ft.
<span>Plug that in the equation, we get 1/2 * 2 * 10. We multiply the 2 and 10 first to get 20, that leaves us with 1/2 x 20, which is 10, so the area of this kite is 10 ft squared.</span>