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3 years ago

X^2+13x+30 How do I factor this? will give brainiest

Chemistry

2 answers:

podryga [215]3 years ago

7 0

Answer:

(x+10) (x+3)

Explanation:

1) this quadratic equation is in the form of: ax^2+bx+c

where we need to figure out what*what=c(30)

and what+what=13(b)

factors of 30: -1,-30 1,30 2,15 -2,-15 3,10 -3,-10 5,6 -5,-6

factors of 30 which equal 13: 3,10

lets substitute 3 and 10 in lace of 13x to factor by grouping:

x^2+3x+10x+30

make two sets:

set a) x^2+3x

set b) 10x+30

the GCF in set a is "x":

x(x+3)

The Gcf in set b is 10:

10(x+3)

now combine the terms outside the parantheses:

(x+10)(x+3)=0

Hope this helps!

3241004551 [841]3 years ago

3 0

Answer:

so you need to use the box method. see attachment below.

Explanation:

so you put the squared number in the top left box

then x value in the middle circle

then the other number in the bottom right box

then, you decide how you get x^2 which is x times x, so you put an x on either side of the x corner

then you decide what time what will equal 30, but ALSO add up to 13

in this case it was 3 and 10, because 3x10 is 30 and 3+10 is 13

then multiply the x times 3 and 10 to fill in the other two boxes

hope this helped!

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BARSIC [14]

The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of $SO_2$ molecules in 9.87 moles $SO_2$ is 59.43 molecules.

The moles of Fe in 1.40 x $10^{22}$ atoms of Fe is 0.23 x $10^{-1}$

The moles of $C_2H_6O$ in 2.30x $10^{24}$ molecules of $C_2H_6O$ is 3.81.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × $10^{23}$ x 0.524 mole

3.155601758 atoms =3.155 atoms

B. The number of $SO_2$ molecules in 9.87 moles of $SO_2$ :

6.02214076 × $10^{23}$ x 9.87

59.4385293 molecules= 59.43 molecules

C. The moles of Fe in 1.40 x $10^{22}$ atoms of Fe:

1.40 x $10^{22}$ ÷ 6.02214076 × $10^{23}$

0.2324754694 x $10^{-1}$ moles.

0.23 x $10^{-1}$ moles.

D. The moles of $C_2H_6O$ in 2.30x $10^{24}$ molecules of $C_2H_6O$ :

2.30x $10^{24}$ ÷ 6.02214076 × $10^{23}$

3.819239854 moles=3.81 moles

Learn more about moles here:

brainly.com/question/8455949

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6 0

2 years ago

How can I balance this equation? ____ KClO3 ---> ____ KCl + ____ O2

tensa zangetsu [6.8K]

__ KClO₃ → __ KCl + __ O₂

Left Side:
1 K
1 Cl
3 O

Right Side:
1 K
1 Cl
2 O

Since the least common multiple of 3 and 2 is 6, we need to multiply the compound with 2 oxygen by 3 and the compound with 3 oxygen by 2.

This gives us 2KClO₃ → __ KCl + 3O₂.

However, this equation is still not balanced.

Left Side:
2 K
2 Cl
6 O

Right Side:
1 K
1 Cl
6 O

In order to balance the K and Cl, we need to multiply the KCl compound on the right side by 2.

2KClO₃ → 2KCl + 3O₂

8 0

3 years ago

A period of the periodic table ends with the highest energy level of an element's ators<br> having?"

andrey2020 [161]

Answer:

the last period. i think has the largest energy level

Explanation:

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2 years ago

Calculate the total energy, in kilojoules, that is needed to turn a 46 g block

neonofarm [45]

Answer: The total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

Explanation:

Given: Mass = 46 g

Initial temperature = $-25^{o}C$

Final temperature = $100^{o}C$

Specific heat capacity of ice = 2.05 $J/g^{o}C$

Formula used to calculate the energy is as follows.

$q = m \times C \times (T_{2} - T_{1})$

where,

q = heat energy

m = mass

C = specific heat capacity

$T_{1}$ = initial temperature

$T_{2}$ = final temperature

Substitute the values into above formula as follows.

$q = m \times C \times (T_{2} - T_{1})\\= 46 g \times 2.05 J/g^{o}C \times (100 - (-25))^{o}C\\= 11787.5 J (1 J = 0.001 kJ)\\= 11.787 kJ$

Thus, we can conclude that the total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

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3 years ago

Give the measurement following sig fig rules for tools. Do not forget the unit after your number measurement.

In-s [12.5K]

Answer:

Explanation:

You are not really helped by what is hold the liquid. Beakers and cylinders come on a lot of sizes. I hate to be crabby about things like that, but you really need to be aware that the question is slightly flawed (not your fault).

The beaker, you'd be like to get 1 sig digit. You have to be awfully careful about claiming more. So the and is 50 mL, but that mL is a guess and the 50 is not totally accurate, but what would you say the second digit is? 48 or 47? You don't really know. Maybe even 49.

The graduated cylinder is a little better. Read the bottom of the meniscus (the bottom of the 1/2 bubble). I think you can get 2 sig digs., so the answer is 36 mL. But everything also depends on what you have been told.

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3 years ago