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Lilit [14]
3 years ago
6

What element would be found in period 5 that has similar chemical properties to Al?

Chemistry
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:

Indium

Explanation:

That is Indium (In) which is in same group as Al

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Of the following elements, which one would have the smallest ionization energy ?
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D. Lithium or Li has the smallest ionization energy of those listed with an energy of 5,3917.

I hope that helps u!

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What would be a simple way to prevent erosion
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3 years ago
What is the density of motor oil in g/mL if 1.25 quart (qt) weighs 2.25 pounds (lb)?
Doss [256]

Answer:

0.86 g/mL

Explanation:

In order to solve the problem, you have to know the formula for "Density." Density refers to<em> </em><em>"mass per unit volume." </em><em>It's formula is:</em>

  • <em>Density (ρ) = </em>\frac{mass}{Volume}<em />

Next, we have to convert the units of measurement in accordance to what is being asked in the problem. It is asking for "g/mL," which means we have to convert 1.25 quarts<em> (qt.) </em>to mL and 2.25 pounds<em> (lbs.)</em> to grams.

Let's solve.

  • 1 quart = 946.35 mL

1.25 qt. x \frac{946.35 mL}{1 qt.} =<em> 1,182.94 mL</em>

  • 1 pound = 453.592 grams

2.25 pounds x \frac{453.592 grams}{1 pound} = <em>1,020.58 grams</em>

Now that we converted them to their appropriate units of measurement, we can now solve for density.

  • <em>ρ = </em>\frac{mass}{Volume}<em />
  • <em>ρ = </em>\frac{1,020.58 grams}{1,182.94 mL}<em />
  • <em>ρ = 0.86 g/mL</em>

<em>The density of the motor oil is 0.86 g/mL</em>

5 0
3 years ago
A cylinder with a movable piston originally has a volume of 2805 mL and is filled with nitrogen to a pressure of 4.00
Sergio039 [100]

This problem is providing the initial volume and pressure of nitrogen in a piston-cylinder system and asks for the final pressure it will have when the volume increases. At the end, the answer turns out to be 2.90 atm.

<h3>Boyle's law</h3>

In chemistry, gas laws are used so as to understand the volume-pressure-temperature-moles behavior in ideal gases and relate different pairs of variables.

In this case, we focus on the Boyle's law as an inversely proportional relationship between both pressure and volume at constant both temperature and moles:

P_1V_1=P_2V_2

Thus, we solve for the final pressure by dividing both sides by V2:

P_2=\frac{P_1V_1}{V_2}

Hence, we plug in both the initial pressure and volume and final volume in order to calculate the final pressure:

P_2=\frac{2805mL*4.00atm}{3864mL}\\ \\P_2=2.90atm

Learn more about ideal gases: brainly.com/question/8711877

6 0
2 years ago
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