Answer:

Explanation:
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In this case, since the equation we use to model the heat exchange into the calorimeter and compute the heat of reaction is:

We plug in the mass of water, temperature change and specific heat to obtain:

Now, this enthalpy of reaction corresponds to the combustion of propyne:

Whose enthalpy change involves the enthalpies of formation of propyne, carbon dioxide and water, considering that of propyne is the target:

However, the enthalpy of reaction should be expressed in kJ per moles of C3H4, so we divide by the appropriate moles in 7.00 g of this compound:

Now, we solve for the enthalpy of formation of C3H4 as shown below:

So we plug in to obtain (enthalpies of formation of CO2 and H2O are found on NIST data base):

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Answer: it would be 0.026 moles
Explanation: PV=nRT, P is the pressure of gas, V is the volume it occupies n is the number of moles of gas present in the sample, R is the universal gas constant which is equal to 0.0821 atm L/mol K and T is the absolute temperature of the gas
Answer:
136.33 million mi
or
1.5 astronomical units (AU)
Explanation:
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A thermometer is used to measure it because the scientific definition of temperature is the average kinetic energy of individual particles in a substance
The radius is proportional to the ionization energy.
This is because electrons are drawn closer to protons, which have opposite charges and hence cling to them, in a small-radius atom.
If the radius is bigger, the electrons on the outside edge of the atom are not as tightly bound and are therefore more easily lost, requiring less energy to ionize.
Factors are more shielding (from core electrons) in the lowest elements of a family, allowing electrons to escape more easily. For those who are currently in a period, the effective nuclear charge grows as the period progresses (more protons, but no more energy levels, so the electrons are the same distance from the nucleus). This causes the electrons to be held closer together (smaller radius), requiring more energy to ionize them.