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1 year ago

Question 3

Chemistry

1 answer:

harina [27]1 year ago

4 0

Answer: 0.118M

Explanation:

The formula for molarity is: $M=\frac{mol solute}{L solution}$

First, we need to find the number of moles of NaCl.

$2.70gNaCl*\frac{1molNaCl}{58.44gNaCl} =0.05molNaCl$

Next, we must convert millimeters to liters. We can do that by dividing the number of mL by 1000.

$\frac{425mL}{1000} =0.425L$

Now we have our needed data! All we need to do now is plug in our data to the molarity formula.

$M=\frac{0.05mol}{0.425L} =0.118M$

I hope this helps! Pls mark brainliest!! :)

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A chemist prepares a solution of sodium thiosulfate by measuring out of sodium thiosulfate into a volumetric flask and filling t

marshall27 [118]

Mass of sodium thiosulfate $Na_{2}S_{2}O_{3}$ is 110. g

Volume of the solution is 350. mL

Calculating the moles of sodium thiosulfate:

$110. g Na_{2}S_{2}O_{3} * \frac{1 mol Na_{2}S_{2}O_{3}}{158.1 g Na_{2}S_{2}O_{3}}$ = 0.696 mol $Na_{2}S_{2}O_{3}$

Converting the volume of solution to L:

$350. mL * \frac{1 L}{1000 mL} = 0.350 L$

Finding out the concentration of solution in molarity:

$\frac{0.696 mol}{0.350 L} = 1.99 mol/L$

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3 years ago

What is the difference between intermolecular forces and intramolecular forces

MrMuchimi

Answer:

Intramolecular forces are the forces that hold atoms together within a molecule. Intermolecular forces are forces that exist between molecules.

Explanation:

Examples: Intermolecular forces are categorized into dipole-dipole forces, London dispersion forces and hydrogen bonding forces.

Intramolecular forces are categorized into covalent, ionic and metal bonds

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2 years ago

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GaryK [48]

Answer:

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Explanation:

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2 years ago

Ethanol has a density of 0.789 g/cm3. What is the mass of 423 cm3 of ethanol? M = (D)(V)

Ivahew [28]

Answer:

<h2>The answer is 334 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of ethanol = 423 cm³

density = 0.789 g/cm³

So we have

mass = 0.789 × 423 = 333.747

We have the final answer as

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3 years ago

What is the ph of a buffer prepared by adding 0.607 mol of the weak acid ha to 0.609 mol of naa in 2.00 l of solution? the disso

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Given:

0.607 mol of the weak acid

0.609 naa

2.00 liters of solution

The solution for finding the ph of a buffer:

[HA] = 0.607 / 2.00 = 0.3035 M
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pH = 6.25 + log 0.3045/ 0.3035 = 6.25 is the ph buffer prepared.

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2 years ago