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nadezda [96]
2 years ago
6

Question 3

Chemistry
1 answer:
harina [27]2 years ago
4 0

Answer: 0.118M

Explanation:

The formula for molarity is: M=\frac{mol solute}{L solution}

First, we need to find the number of moles of NaCl.

2.70gNaCl*\frac{1molNaCl}{58.44gNaCl} =0.05molNaCl

Next, we must convert millimeters to liters. We can do that by dividing the number of mL by 1000.

\frac{425mL}{1000} =0.425L

Now we have our needed data! All we need to do now is plug in our data to the molarity formula.

M=\frac{0.05mol}{0.425L} =0.118M

I hope this helps! Pls mark brainliest!! :)

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How are intermolecular forces different between polar and nonpolar molecules
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Answer:

Explanation: Polar molecules interact with each other by forces such as dipole-dipole interactions whereas nonpolar molecules interact with each other through London dispersion forces

5 0
2 years ago
1. What is the pressure on 2.5 L, if the initial pressure was 400 mmHg and the
S_A_V [24]

Answer:

The answer to your question is   P2 = 280 mmHg

Explanation:

Data

Pressure 1 = P1 = 400 mmHg

Volume 1 = V1 = 1.75 L

Pressure 2 = ?

Volume 2 = 2.5 L

Process

1.- Use Boyle's law to solve this problem

                  P1V1 = P2V2

-Solve for P2

                     P2 = P1V1 / V2

2.- Substitution

                    P2 = (400)(1.75) / 2.5

3.- Simplification

                   P2 = 700 / 2.5

4.- Result

                   P2 = 280 mmHg

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3 years ago
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Is a compound is made different of<br> atoms?
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4 0
3 years ago
What mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution?
Naddik [55]

383.5 grams is the mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution.

Explanation:

Given that:

Solution to be prepared is 5.5 %

mass of KCl is 22 gram

mass of water required =?

5.5 % solution means that

5.5 grams in 100 ml or gram of water to make solution.

let the water required is 5.5 + x, so the equation will be

5.5 =\frac{22}{22+x} x 100

121+ 5.5x = 2200

5.5 x = 2200-121

     x = \frac{2079}{5.5}

    x = 378 grams

The mass of water added to KCl to make it 5.5% percent solution is

5.5 +378

= 383.5 grams.

to make the solution of 5.5 percent of KCl weighing 22 grams.

8 0
3 years ago
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