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MrRissso [65]
3 years ago
5

You run a ten-kilometer race in 45.5 minutes. Write an inequality for the time of the runners who finished the race after you di

d.
Mathematics
1 answer:
julsineya [31]3 years ago
5 0

Answer:

If a runner is behind you, s/he must have taken longer, so the times of all of the runners who finished after you did must be greater than 45.5 minutes

Step-by-step explanation:

Hmu if you need more help or sum!

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Write an equation of the perpendicular bisector of the line segment whose endpoints are (−1,1) and (7,−5)
icang [17]

The equation is y = \frac{3}{2} x - \frac{11}{2}

<u>Explanation:</u>

We have to first find the mid-point of the segment, the formula for which is

(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )

So, the midpoint will be (\frac{-1+7}{2} , \frac{1-5}{2} )\\\\

                                  = (3,-2)

It is the point at which the segment will be bisected.

Since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula \frac{y_2-y_1}{x_2-x_1}

The slope is \frac{-5-1}{7+1} = -\frac{2}{3}

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of  -\frac{2}{3} is \frac{3}{2}

To write an equation, substitute the values in y = mx + c

WHere,

y = -1

x = 3

m = 3/2

Solving for c:

-1 = \frac{3}{2} X 3 + c\\\\-1 = \frac{9}{2}+c\\ \\c = \frac{-2-9}{2} \\\\c = \frac{-11}{2}

Thus, the equation becomes:

y = \frac{3}{2} x - \frac{11}{2}

7 0
3 years ago
2/5g = 3/5<br><br> What does is solve to? <br> Give me a brief explanation please
swat32

Answer:

The answer is 1 and 1/2 or 1.5.

Step-by-step explanation:

I did 3/5 ÷ 2/5. Then I got 3/2. Then I turned the improper fraction into a mixed number.

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3 years ago
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ruslelena [56]

Answer:

<u>1.56 is greater than 1.29</u>. (Check after the decimal point, 5 is greater than 2, so 1.56 is greater than 1.29)

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2 years ago
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it is a have a great day xoxoxoxoxoxo

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3 years ago
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Can anyone tell me correctly​
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\large\underline\red{\sf \implies Solution :- }

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