All categories

3 years ago

Please help I will mark you brainlist if correct

Mathematics

2 answers:

weqwewe [10]3 years ago

8 0

You have to rearrange this so the equation will equal y :

$x + 2y = 5$
Now take away x from both sides. This will leave you with :
$2y = 5 - x$
As you can see the equation is equal to y, however, there is a 2 next to the y so we need to get rid of that.
So 2y basically means : 2* y
And the opposite of * is divide, which means we have to divide both sides by 2, which will leave us with our answer :
$y = (5 - x) \div 2$

emmasim [6.3K]3 years ago

7 0

Y=(5-x)/2 thats the answer

You might be interested in

Factor the expression. 40z – 20

erik [133]

$40z - 20$

$GCF=20
$

$20 ( \dfrac{40z}{20} - \dfrac{20}{20})$

$20(2z-1)$

7 0

3 years ago

Read 2 more answers

Guys please help with this question thanks

erastova [34]

= 16 + 49 - 3(11) - 4(10)
= 16 + 49 - 33 - 40
= -8

3 0

2 years ago

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0

2 years ago

A loan officer makes $15 per hour working 2,000 hours each year. She also gets a fee of $35 for each loan she processes. If she

Afina-wow [57]

Answer:

$61,500

Step-by-step explanation:

For this problem, we will simply take her hourly wage and multiply that by the hours she worked and take her additional earnings for each loan processed and multiply that by the number of loans she processed.

Consider her hourly wage of $15 per hour. If she worked 2000 hours, then we can say she got paid ($15 * 2000) = $30000 for her work that year.

Consider her processing fee of $35 per loan processed. If she processed 900 loans, then we can say she got paid ($35 * 900) = $31500 for her processed loans that year.

Then, to find her yearly total earnings, we simply add those two values. $30000 + $31500 = $61500.

Thus the loan officer made $61500 that year.

Cheers.

7 0

2 years ago

Read 2 more answers

Multiplying binomials Determine the product (x-3) (x-8)

MrMuchimi

X^2-24 is the answer

4 0

2 years ago

Read 2 more answers