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slavikrds [6]
4 years ago
6

Please help I will mark you brainlist if correct

Mathematics
2 answers:
weqwewe [10]4 years ago
8 0
You have to rearrange this so the equation will equal y :

x + 2y = 5
Now take away x from both sides. This will leave you with :
2y = 5 - x
As you can see the equation is equal to y, however, there is a 2 next to the y so we need to get rid of that.
So 2y basically means : 2* y
And the opposite of * is divide, which means we have to divide both sides by 2, which will leave us with our answer :
y = (5 - x) \div 2



emmasim [6.3K]4 years ago
7 0
Y=(5-x)/2 thats the answer

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3 years ago
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3 years ago
14. The diagonals of square ABCD intersect at E. If AE = 2, find the perimeter of ABCD.
lutik1710 [3]

Answer:

B, 8\sqrt{2}

Step-by-step explanation:

Diagonals of a square are congruent so AC= 4

using pythagorean theorem we can then do x^{2} +x^{2}=4^{2}

2x^{2} = 16\\x^{2} =8\\x=\sqrt{8} \\x=2\sqrt{2}

Then for perimeter we times the 2\sqrt{2} by 4 and get

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8 0
3 years ago
If v1 = (2,-5) and v2 = (4,-3), then the angle between the two vectors is _________. Round your answer to two decimal places.
siniylev [52]
The angle between two vectors is given by:
 cos (x) = (v1.v2) / (lv1l * lv2l)
 We have then:
 v1.v2 = (2, -5). (4, -3)
 v1.v2 = (2 * 4) + (-5 * (- 3))
 v1.v2 = 8 + 15
 v1.v2 = 23
 We look for the vector module:
 lv1l = root ((2) ^ 2 + (-5) ^ 2)
 lv1l = 5.385164807
 lv2l = root ((4) ^ 2 + (-3) ^ 2)
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 Answer:
 
The angle between the two vectors is:
 
x = 31.33 degrees
3 0
3 years ago
Solve the following quadratic equation for all value of c i'm simplest form <br> 5(x-2)^2=20
xz_007 [3.2K]

Answer:

x=-2 and x=0

Step-by-step explanation:

5(x-2)^2 =  20; divide by 5 both sides

(x-2)^2 = 4; take the square root of both sides

(x-2) = ±2, now set it equal to positive 2 and negative 2

x-2 = 2

x=4

AND

x-2 = -2

x=0

8 0
3 years ago
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