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4vir4ik [10]
3 years ago
5

Reduce to lowest term18/24

Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0
18/24

Find the HCF of the numerator and denominator and divide them by it.

In this case, its 6


18/24 ÷ 6/6 = 3/4
qwelly [4]3 years ago
4 0
A common number is 6 so divide 18 and 24 by 6. you get the total of 3/4 <span />
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Which measure of center is the best to use to compare the prices of kid socks and adult socks?
k0ka [10]

Answer:

The answer is mean

Step-by-step explanation:

The mean is the average cost of the socks, so finding the mean of both would give an average price to compare them to. :)

3 0
3 years ago
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Which is the graph of f(x) = 100(0.7)*?
mario62 [17]

Answer and Step-by-step explanation:

Here's~the~answer~to~your~question!

3 0
3 years ago
Learning Theory Students in a psychology experiment were given an exam and then retested monthly with equivalent exams. The aver
forsale [732]

Answer:

Step-by-step explanation:

The average scores s (on a 100 point scale) for the students can be modeled by

s = 75 - 6 In(t + 1), 0 < t < 12

where t is the time in months.

a) Since the students were given an exam and then retested monthly with equivalent exams, then,

For the original exam, t = 0

Therefore,

s = 75 - 6 In(0 + 1) = 75 - 6 In1

s = 75 - 6 × 0 = 75

b) the average score after 4 months, t = 4

Therefore,

s = 75 - 6 In(4 + 1) = 75 - 6 In5

s = 75 - 9.66 = 65.34

c) s = 60

Therefore,

60 = 75 - 6 In(t + 1)

6 In(t + 1) = 75 - 60 = 15

In(t + 1) = 15/6 = 2.5

t + 1 = e^2.5 = 12.18

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8 0
3 years ago
The values of a sample statistic for different random samples of the same size from the same population will be the same.
Rus_ich [418]

Answer:

In general, sample statistics will tend to be different. With continuous random variables, this should always be the case (until rounding, which brings us back to "actually that's just theoretically continuous") and with discrete random variables this will often be the case with some statistics and perhaps more often not with others (how often it depends on the distribution pattern, sample size, and the particular statistics you are viewing).

Step-by-step explanation:

You can response your particular query by straight experiment, in simple cases.

For example, consider rolling a particular six-sided die (a well-made one that's very close to fair). You could withdraw two samples of some wanted size (n1 = 20

and n2 = 20 say) and calculate your sample statistics. I suggest you try it!

Actually, not being one to ask you to try something I wouldn't do myself, here are my attempts, first with one die (two samples each of size 20) and then a repeat with a different die:

Result of die A: 1 2 3 4 5 6

Sample 1 (Counts) 2 3 3 2 4 6

Sample 2 6 2 3 4 3 2

Result of die B: 1 2 3 4 5 6

Sample 1 (Counts) 3 7 3 0 3 4

Sample 2 1 4 1 5 4 5

And here are some summary statistics:

Die A Range median mean sd

Sample 1 5 4.5 4.05 1,791

Sample 2 5 3 3.10 1,774

Die B Median Mean Range SD

Sample 1 5 2.5 3.25 1,860

Sample 2 5  4  4.10 1,619

If you do, you will probably get the same maximum and minimum both times (I would expect both 1 and 6 to show in a sample of 20 about 95% of the time), but the means and standard deviations would be different.

The medians could be the same (about a 25% chance of that, with the usual definition of sample median even for n

), but easily not.

There is some chance of obtaining the same mean for two of these (because we are sampling a discrete distribution with only a few results), but there is a low probability of seeing it (around 3.7%);

You can also get the same standard deviation, but the chance is much less ... about 2/3 of a percentage.

At larger or smaller sample sizes, those possibilities change; and they change again if you extract from other distributions other than that of a (roughly) fair die.

That all those statistics I mentioned would be the same would be highly unlikely.

3 0
3 years ago
If BE ≅ LU in quadrilateral BLUE shown, which additional information would be sufficient to prove quadrilateral BLUE is a parall
goblinko [34]

Answer: Option A and option B would be sufficient to prove that BLUE is a parallelogram. The diagonals are congruent IS NOT ALWAYS TRUE about a parallelogram.

Step-by-step explanation: Please refer to the diagram attached for details. One of the properties of a parallelogram is that each pair of opposite sides are equal to each other. So lines BE and LU are parallel as shown by the arrows on both lines in the attached picture. Same applies to lines BL and EU. Line BE doesn’t have to be congruent to BL, but BE must be congruent to LU. Same applies to BL and EU. Also in a parallelogram, opposite sides are congruent, opposite angles are congruent (angle B = angle U and angle E = angle L) and opposite sides are parallel. The diagonals are NOT ALWAYS congruent. This is only possible if all four sides are of the same measurement. However if for instance, side BE does not equal BL, then the diagonals cannot be equal.

8 0
3 years ago
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