1.) 1:4
4.) 2:3
5.) 7:9
6.) 1:7
Answer:
17/28
if you're solving for cosine
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) 5 2)20 3)3 4) 12
5) 9 6)18 7) 3 8) 20
9) 27 10)15 11)5 12)18
Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
4t+ 14= 6t/5+ 7
⇒ 4t+ 14= 6/5t+ 7
⇒ 4t -6/5t= 7 -14
⇒ (4 -6/5)t= -7 (distributive property)
⇒ 14/5t= -7
⇒ t= -7/ (14/5)
⇒ t= -5/2
⇒ t= -2.5
Final answer: t= -2.5~