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3 years ago

The table shows how many of each type of movie are being shown at a theater.

Mathematics

1 answer:

alexira [117]3 years ago

7 0

Answer:

ratio is 5isto 4 byan action and drama

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I NEED HELP PLS!!!! I DONT UNDERSTAND THIS!! PLS TELL ME THE CORRECT ANSWER AND HOW YOU GOT IT STEP BY STEP!!!!

padilas [110]

I like to start with changing fractions to decimals. It seems easier that way.
5/8 = 0.625 cups

Now divide 4 by 0.625
4 / 0.625 = 6.4

Noor can offer 6 cups with an extra 2/5 of a cup left. He can offer the 2/5 of a cup to a friend, so he can offer 7 friends some hot chocolate!

5 0

3 years ago

Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the

ludmilkaskok [199]

By Stokes' theorem,

$\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$

where $\mathcal C$ is the circular boundary of the hemisphere $\mathcal M$ in the $y$ - $z$ plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

$\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle$

where $0\le t\le2\pi$ . Then the line integral is

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt$
$=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi$

We can check this result by evaluating the equivalent surface integral. We have

$\nabla\times\mathbf f=\langle1,0,0\rangle$

and we can parameterize $\mathcal M$ by

$\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle$

so that

$\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv$

where $0\le v\le\dfrac\pi2$ and $0\le u\le2\pi$ . Then,

$\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi$

as expected.

7 0

3 years ago

The lengths of the sides of a triangle are in the ratio

Anton [14]

HOW TO SOLVE:

1) use x as a variable
2) the starting equation is:
  4x + 3x + 5x = 18

3) add all the like terms on the left side of the equation:
  12x = 18

4) Divide by 12 on both sides:
  x=1.5

5) Find the lengths of the sides:

- 4x = 4(1.5) = 6

- 3x = 3(1.5) = 4.5

- 5x = 5(1.5) = 7.5

SO, the lengths of the sides of this triangle are: 6, 4.5, and 7.5

5 0

3 years ago

(w-w^2)^4=?<br>.......................

Setler [38]

Answer:

w^8 - 4w^7 + 6w^6 - 4w^5 + w^4 .

Step-by-step explanation:

(w - w^2)^4

= w^4 ( 1 - w)^4

By the binomial theorem:

= w^4( 1 - 4w + 6w^2 - 4w^3 + w^4)

= w^4 - 4w^5 + 6w^6 - 4w^7 + w^8

= w^8 - 4w^7 + 6w^6 - 4w^5 + w^4 ( Standard form).

3 0

3 years ago

Figure ABCD is a parallelogram.

bogdanovich [222]

A = C (congruent angles)

Then: 4p+12 = 36

Solve for p

4p = 36 - 12

4p = 24

4p/4 = 24/4

p = 6

Answer is going to be A.

6 0

3 years ago

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