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3 years ago

Plz answer with explanation will choose brainliest

Mathematics

1 answer:

Mrrafil [7]3 years ago

3 0

Answer:

The answer is A.

Step-by-step explanation:

When finding the distance, you have to subtract the two numbers and take the absolute the value of that difference.

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Jason is building a 1 : 180 scale model of a real castle. his model has a rectangular base that is 3 feet wide and 4 feet long.w

balu736 [363]

The area of the actual castle would be 388,800 sq. ft.

We would multiply each of the sides of the scale model both by 180 to find the side lengths of the actual castle.

So...
180 x 4 = 720
180 x 3 = 540

If Area is equal to Length Times Width, all thats left to do is to multiply the two sides together.

720 x 540 = 388,800

Hope this helped! :D

3 0

2 years ago

Select the answer that contains one countable noun and one uncountable noun

elena-14-01-66 [18.8K]

Mamdiiajfhxtxusisudjdsusi

3 0

2 years ago

Volume of the cylinder=?

lyudmila [28]

Answer:

628.32

Step-by-step explanation:

Volume:

πr2h

=π×52×8

= 200π

= 628.31853071796

6 0

1 year ago

Read 2 more answers

CAN SOMEONE HELP PLEASE ASAP!!! ILL MAKE YOU BRAINLIEST

Anastaziya [24]

Answer:

I think the answer is D but I'm not 100 percent sure. I hope this helps

Step-by-step explanation:

I think I took this test before

8 0

2 years ago

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

8 0

2 years ago