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Alla [95]
4 years ago
13

a material has a density of 8.9 g/cm^3. you have three cubic centimeters of the substance. what is the material's mass in grams?

Chemistry
2 answers:
Paha777 [63]4 years ago
5 0

Answer:

26,7 g

Explanation:

8,9[\frac{g}{cm^3}]*3[cm^3]=26,7[g]

As you see in the maths, if you have 8,9 grams per each cubic centimeter, in 3 cubic centimeter you'll have 3 times 8,9

34kurt4 years ago
4 0

Answer: 26.7 grams

Explanation:

We know that the formula to calculate the mass is given by :-

{\text{Mass}=\text{Density}\times\text{Volume}

We are given that the density of material is 8.9\ g/cm^3.

Volume of material = 3 cubic centimeters

Then , substitute the value of density and volume in the above formula , we get

{\text{Mass}=8.9\times3= 26.7\ g

Hence, the required material's mass =  26.7 grams

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3 0
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Be sure to answer all parts. A person drinks four glasses of cold water (3.2 degree C) every day. The volume of each glass is 2.
Lelechka [254]

Explanation:

(a). The given data is as follows.

Volume of one glass of water = 2.2 \times 10^{2} ml = 220 ml

Volume of 4 glass of water = 220 \times 4 = 880 ml

We known that density of water is 1 g/ml.  Therefore, calculate the mass of water as follows.

       Mass of water = 880 ml \times 1 g/ml

                               = 880 gm

                               = 0.88 Kg               (as 1 kg = 1000 g)

The relation between heat energy, mass and temperature change is as follows.

            Q = mC \Delta T

\Delta T = (37 - 3.2)^{o}C = 33.8^{o}C

Putting the given values into the above formula as follows.

         Q = mC \Delta T

             = 0.88 \times 4.186 J/g^{o}C \times 33.8^{o}C

             = 124.5 kJ

Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.

(b).      As we know that the heat of fusion of ice is 333 J/g.

So, energy required for 8.4 \times 10^{2} g or 840 g is as follows.

          333 \times 840 = 279.72 kJ

Heat capacity of water= 4.184 J/g^{o}C

Now, heat energy will be as follows.

           Q = 4.184 \times 840 g \times 37^{o}C

               = 130.03 kJ

Therefore, total heat required = (279.72 + 130.03) kJ

                                                  = 409.75 kJ

Hence, for the given situation your body should lose 409.75 kJ  of heat.

6 0
4 years ago
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Answer:

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The fault here is the unforeseen energy order of molecular orbitals. Since if filled, sigma 2px will be firmly pushed away by the electron density of orbitals already filled with sigma 2s (both electron densities lie on the inter-nuclear axis). Because of this, sigma 2px's energy is found shockingly greater than pi 2py and pi 2pz.

The electrons therefore occupy pi 2py and pi 2pz orbitals as opposed to normal sigma 2px (which remains vacant) while filling.

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