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3 years ago

a material has a density of 8.9 g/cm^3. you have three cubic centimeters of the substance. what is the material's mass in grams?

Chemistry

2 answers:

Paha777 [63]3 years ago

5 0

Answer:

26,7 g

Explanation:

$8,9[\frac{g}{cm^3}]*3[cm^3]=26,7[g]$

As you see in the maths, if you have 8,9 grams per each cubic centimeter, in 3 cubic centimeter you'll have 3 times 8,9

34kurt3 years ago

4 0

Answer: 26.7 grams

Explanation:

We know that the formula to calculate the mass is given by :-

${\text{Mass}=\text{Density}\times\text{Volume}$

We are given that the density of material is $8.9\ g/cm^3$ .

Volume of material = 3 cubic centimeters

Then , substitute the value of density and volume in the above formula , we get

${\text{Mass}=8.9\times3= 26.7\ g$

Hence, the required material's mass = 26.7 grams

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Answer:

B. Wall applies equal reaction force on hand

Explanation:

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2 years ago

A diffusion coefficient KG was determined for the diffusion of a gas A through a stagnant film B [KG = 0.88 mol//h-ft2-atm].

Angelina_Jolie [31]

Explanation:

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$N_{A} = K_{G} \times (P_{A1} - P_{A2})$

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4 0

4 years ago

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Lisa [10]

Answer:

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3 years ago

A sample of sulfur hexafluoride gas occupies a volume of 5.10 L at 198 ºC. Assuming that the pressure remains constant, what tem

Ludmilka [50]

Answer:

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

Explanation:

Step 1: Data given

A sample of sulfur hexafluoride gas occupies a volume of 5.10 L

Temperature = 198 °C = 471 K

The volume will be reduced to 2.50 L

Step 2 Calculate the new temperature via Charles' law

V1/T2 = V2/T2

⇒with V1 = the initial volume of sulfur hexafluoride gas = 5.10 L

⇒with T1 = the initial temperature of sulfur hexafluoride gas = 471 K

⇒with V2 = the reduced volume of the gas = 2.50 L

⇒with T2 = the new temperature = TO BE DETERMINED

5.10 L / 471 K = 2.50 L / T2

T2 = 2.50 L / (5.10 L / 471 K)

T2 = 230.9 K = -42.1

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

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3 years ago

A balloon contains 2.0 L of air at 101.5 kPa. You squeeze the balloon to a volume of .75 L. What is the pressure of air on the i

Nataly_w [17]

You would use the formula for Boyle's Law:

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P = Pressure

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3 0

3 years ago

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