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Svetach [21]
3 years ago
5

How many moles of sodium chloride (NaCl) solute are in 315 grams of a 91.0 percent by mass solution?

Chemistry
1 answer:
Anni [7]3 years ago
8 0
Hope this helps you.

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Which of the following shows the wavelengths of light that an atom gives off when an electron falls to a lower energy level?
charle [14.2K]

The wavelengths of light that an atom gives off when an electron falls to a lower energy level corresponds to Emission spectrum , Option D is the correct answer.

<h3>What is Emission Spectrum ?</h3>

Light is absorbed or emitted when an electron jumps or falls into an energy level.

The energy of light absorbed or emitted is equal to the difference between the energy of the orbits.

Therefore , the wavelengths of light that an atom gives off when an electron falls to a lower energy level corresponds to Emission spectrum.

To know more about Emission Spectrum

brainly.com/question/13537021

#SPJ1

3 0
1 year ago
What intermolecular force attracts two non polar molecules to each other
Salsk061 [2.6K]

The intermolecular force that attracts two nonpolar molecules is London dispersion forces, which are also called induced dipole-induced

3 0
2 years ago
A certain substance melts at a temperature of . But if a sample of is prepared with of urea dissolved in it, the sample is found
pshichka [43]

Answer:

2.2 °C/m

Explanation:

It seems the question is incomplete. However, this problem has been found in a web search, with values as follow:

" A certain substance X melts at a temperature of -9.9 °C. But if a 350 g sample of X is prepared with 31.8 g of urea (CH₄N₂O) dissolved in it, the sample is found to have a melting point of -13.2°C instead. Calculate the molal freezing point depression constant of X. Round your answer to 2 significant digits. "

So we use the formula for <em>freezing point depression</em>:

  • ΔTf = Kf * m

In this case, ΔTf = 13.2 - 9.9 = 3.3°C

m is the molality (moles solute/kg solvent)

  • 350 g X ⇒ 350/1000 = 0.35 kg X
  • 31.8 g Urea ÷ 60 g/mol = 0.53 mol Urea

Molality = 0.53 / 0.35 = 1.51 m

So now we have all the required data to <u>solve for Kf</u>:

  • ΔTf = Kf * m
  • 3.3 °C = Kf * 1.51 m
  • Kf = 2.2 °C/m
5 0
2 years ago
All of the alkali earth metals, Group 2, have two valence electrons. Which of these would represent the oxidation number of the
chubhunter [2.5K]
Since Group 2 alkali earth metals have 2 valence electrons, they tend to lose those 2 when forming ionic bonds. And the Loss of Electrons = Oxidation (L.E.O. for short). Therefore this group, including Mg and Ca, have an oxidation of [+2].
So the correct answer is C) +2
5 0
3 years ago
Read 2 more answers
If a gas occupies 79.5 mL at -1.4°C, what temperature, in Kelvin, would it
Anna35 [415]

Answer:

121 K

Explanation:

Step 1: Given data

  • Initial volume (V₁): 79.5 mL
  • Initial temperature (T₁): -1.4°C
  • Final volume (V₂): 35.3 mL

Step 2: Convert "-1.4°C" to Kelvin

We will use the following expression.

K = °C + 273.15 = -1.4°C + 273.15 = 271.8 K

Step 3: Calculate the final temperature of the gas (T₂)

Assuming ideal behavior and constant pressure, we can calculate the final temperature of the gas using Charles' law.

V₁/T₁ = V₂/T₂

T₂ = V₂ × T₁/V₁

T₂ = 35.3 mL × 271.8 K/79.5 mL = 121 K

5 0
2 years ago
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