Answer:
1.15 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 55.6 g
Volume (V) = 48.5 mL
Density (D) =?
Density is simply defined as the mass of the substance per unit volume of the substance. It is represented mathematically as:
Density (D) = mass (m) /volume (V)
D = m/V
With the above formula, we can obtain the density of the object as follow:
Mass (m) = 55.6 g
Volume (V) = 48.5 mL
Density (D) =?
D = m/V
D = 55.6/48.5
D = 1.15 g/mL
Therefore, the density of the object is 1.15 g/mL
I think the correct answer from the choices listed above is option A. A can of diet soda will float in water while a can of regular sugar soda will sink. This is due to the reason that the regular soda is more dense than the diet soda. Hope this answers the question.
Diffusion is when molecules go from high concentration to low concentration, and it's faster in summer<span />
Answer:
a) Germanium = 5.76 x 〖10〗^11 〖cm〗^(-3) , Semiconductor is n-type.
b) Silicon = 2.25 x 〖10〗^5 〖cm〗^(-3) , Semiconductor is n-type.
For clear view of the answers: Please refer to calculation 5 in the attachments section.
Explanation:
So, in order to find out the concentration of holes and electrons in a sample of germanium and silicon which have the concentration of donor atoms equals to 〖10〗^15 〖cm〗^(-3). We first need to find out the intrinsic carrier concentration of silicon and germanium at room temperature (T= 300K).
Here is the formula to calculate intrinsic carrier concentration: For calculation please refer to calculation 1:
So, till now we have calculated the intrinsic carrier concentration for germanium and silicon. Now, in this question we have been given donor concentration (N_d) (N subscript d), but if donor concentration is much greater than the intrinsic concentration then we can write: Please refer to calculation 2.
So, now we have got the concentration of electrons in both germanium and silicon. Now, we have to find out the concentration of holes in germanium and silicon (p_o). (p subscript o)
Equation to find out hole concentration: Please refer to calculation 3. and Calculation 4. in the attachment section.
Good Luck Everyone! Hope you will understand.