All categories

2 years ago

Akeem cut his finger during an investigation, and it is bleeding slightly. Before helping him bandage the wound,

Chemistry

2 answers:

Sergio039 [100]2 years ago

7 0

Answer:

2020 Put on protective gloves.

Explanation:

jeka57 [31]2 years ago

4 0

Answer:

b.) Put on protective gloves

You might be interested in

Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

balu736 [363]

Answer:

Cost to supply enough vanillin is $3.2\$$

Explanation:

Threshold limit of vanillin in air is $2.0\times 10^{-11}g$ per litre means there should be $2.0\times 10^{-11}g$ of vanillin in 1L of air to detect aroma of vanillin.

$1ft^{3}=28.32L$

So, $5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L$

So amount of vanillin should be present to detect = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$

As cost of 50 g vanillin is $112\$$ therefore cost of $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$ vanillin = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$$

5 0

2 years ago

The number of molecules in 7g nitrogen

charle [14.2K]

Answer:

the number of molecules in 7g nitrogen

Ans) 7 gram of Nitrogen contains 1.5×10^23 molecules =1.5e+23

5 0

2 years ago

According the inverse square law, doubling the distance from the source of the sound, a speaker, for example, will drop the soun

Shtirlitz [24]

Answer:

Yes, I would be able to hear the speaker clearly because the supposedly dropping off of sound as the distance gets farther is counteracted by "reverberations" inside the auditorium.

Explanation:

According to the "Inverse Square Law," if the distance from the sound source is doubled, the intensity of the sound will diminish by 6 decibels. This is true if the situation is in a "free field," which means the sound has no reflection.

However, this is not the case in an "auditorium." An auditorium causes the "reverberation" of sound. This prolongs the resonance of the sound. So, this means that even if the sound drops off by a factor of 100 (20 decibels), due to reverberations, the height of the ceiling, the kind of wall and materials used in making the seats also affect the intensity of the sound waves. This is the reason why auditoriums are used as venues for concerts, presentations and the like where a large group of people serve as the audience.

4 0

3 years ago

Read 2 more answers

We have a methanol solution that is 6.0 m methanol, CH 3OH in water. Vapor pressure pure water at 30. degrees C is 31.82 mmHg. V

Mashcka [7]

Answer: The total pressure above the solution at 30°C is 45.29 mmHg

Explanation:

We are given:

Molality of methanol = 6.0 m

This means that 6.0 moles of methanol present in 1 kg or 1000 g of pure water

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of water = 1000 g

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

$\text{Moles of water}=\frac{1000g}{18g/mol}=55.56mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

$\chi_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}\\\\\chi_{CH_3OH}=\frac{6}{6+55.56}=0.0975$

$\chi_{water}=\frac{n_{water}}{n_{CH_3OH}+n_{water}}\\\\\chi_{water}=\frac{55.56}{6+55.56}=0.9025$

To calculate the total pressure, we use the equation given by Dalton and Raoults, which is:

$p_T=(p_A\times \chi_A)+(p_B\times \chi_B)$

where,

$p_T$ = total vapor pressure = ?

We are given:

Mole fraction of methanol = 0.0975

Mole fraction of water = 0.9025

Vapor pressure of methanol = 170.0 mmHg

Vapor pressure of water = 31.82 mmHg

Putting values in above equation, we get:

$p_T=(170\times 0.0975)+(31.82\times 0.9025)\\\\p_T=45.29mmHg$

Hence, the total pressure above the solution at 30°C is 45.29 mmHg

6 0

3 years ago

How do the properties of buffered and unbuffered solutions compare?

Elenna [48]

A buffer is something that regulates the pH of a solution. So buffered water will resist changing its pH i.e. add an acid to it and its pH shouldn't change. Unbuffered water is the opposite i.e. normal water.Kush

4 0

3 years ago