First convert mass to number of moles. Molar mass
of H2C2O2 • 2H2O = 94 / mol
1.89g / (94 g / mol) = .02 mol H2C2O2 • 2H2O
Then we divide by 0.1 L, or 100 mL, and we get a
concentration of 0.2 M.
Since there are two positive ions (2 H+), therefore
normality is:
<span>0.4 N</span>
Energy in wind comes from the sun. for example, when the Earth’s surface absorbs the suns energy, it turns to heat. wind is produced by uneven heating from the earths surface by the sun. Since the earth's surface is made of various land and water formations, it absorbs the sun's radiation unevenly. The blades on the wind turbine move from the wind. i hope that made sense, if it didn’t i’m sorry, i hoped that hep though!
The answer depends on what substances you were testing, but here are some ideas.
If all of them were white as in the typical experiment, then color is not very useful. If you were allowed to taste them, then a salty taste would be a helpful clue. If the textures were different, some crystals, like salt or sugar and others powdery, like flour or cornstarch, those properties would be helpful. If some dissolved in water,...
Answer:
Attraction between molecules of methane in liquid state is primarily due to "London dispersion force".
Explanation:
Methane is a non-polar and aprotic molecule. Hence there is no dipole moment in methane as well as no chance of hydrogen bonding formation by methane.
We know that all molecules contain electrons. Therefore transient dipole arises in every molecule due to revolution of electrons around nucleus in a non-circular orbit. Hence an weak intermolecular attraction force is always present in every molecule as a result of this which is termed as "London dispersion force".
So, attraction between molecules of methane in liquid state is primarily due to "London dispersion force".
You have the stoichiometric equation. This tells you unequivocally that an
18
⋅
g
mass of water, 1 mole, reacts with a
56.07
⋅
g
mass of quicklime to form a
74.09
⋅
g
mass of slaked lime.
If you don't from where I am getting these numbers, you should know, and someone will be willing to elaborate.
Here, you have formed
6.21
⋅
m
o
l
of quicklime which requires stoichiometric lime AND water. And thus you need a mass of
6.21
⋅
m
o
l
×
18.01
⋅
g
⋅
m
o
l
−
1
water
≅
88
⋅
g
.
In practice, of course I would not weigh out this mass. I would just pour
100
−
200
⋅
m
L
of water into the lime.
