Answer:
1 = 60 cm. 2 = weeks 4-5
Step-by-step explanation:
Answer:
c. binomial distribution with n = 5 and p = 1/33.
Step-by-step explanation:
For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability of a birth resulting in a defect is independent of other births. So we use the binomial probability distrbution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
The proportion of American births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).
This means that the probability of a birth resulting in a defect is ![p = \frac{1}{33}](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7B1%7D%7B33%7D)
A local hospital randomly selects five births.
This means that ![n = 5](https://tex.z-dn.net/?f=n%20%3D%205)
So the correct answer is:
c. binomial distribution with n = 5 and p = 1/33.
The answer is $60.50, if the 10% is coming from the $55
Answer:
B. 0.32
Step-by-step explanation:
Fractions are basically division, so do 8 divided by 25 and you will get 0.32.