Answer:
a. when x=1 so substitute 1 to any X in the given equation.
y=-3(1)+2.5
y=-3+2.5
y=-0.5
b.when x is -1.5 so substitute -1.5 to any x in the equation
y=-3(-1.5)+2.5
y=-4.5+2.5
y=-2
9514 1404 393
Answer:
B) (2, -5)
D) (3, 0)
Step-by-step explanation:
I find it convenient to let a graphing calculator plot the points and the graph.
The only two points on the graph of the curve are ...
(2, -5) and (3, 0)
C(-8,2) and M(0,0) , since M is at the origin. Let x₁ and y₁ be the
coordinates of S →s(x₁ , y₁)
C(-8,2) and S(x₁ , y₁)
The coordinates of M, the midpoint of CS are M(x₂ , y₂)
a) x₂ = (-8 + x₁)/2 , but x₂ = 0, then :
0 = -4+x₁/2 and x₁ = 8
b) y₂ = (2+y₁)/2 , but y₂ = o, then:
0 = 2+ y₁/2 and y₂ = -2
Then the coordinates of S are S(8 , -2)
Answer:
Step-by-step explanation:
Given that:
sample size n = 36
standard deviation = 10.1
level of significance ∝ = 0.10
The null hypothesis and the alternative hypothesis can be computed as follows:


The test statistics can be computed as follows:





degree of freedom = n - 1 = 36 - 1 = 35
Since this test is two tailed .
The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)
P - value = 2 × 0.435163515
P - value = 0.8703 ( to four decimal places)
Decision Rule : To reject the null hypothesis if P - value is less than the 0.10
Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.