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Orlov [11]
3 years ago
15

jack has 100 football cards that he wants to put in a photo album. Each page in the album will hold eight cards. How many pages

in the album will have cards on them?
Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0
<u>12 albums</u> will be filled with eight pages. But <u>1 will have a album with only 5 pages</u><u />
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Given the vectors w = &lt;-5, 3&gt; and z = &lt;1, 4&gt;, find the results of the vector subtractions. -w − z = z − w = w − z =
Elodia [21]

Answer:

Concept: Linear Algebra

  1. Given two linearly independent vectors w and z
  2. We want -w-z
  3. Hence apply a negative gradient to w
  4. w=-<-5,3> =<5,-3>
  5. So <5,-3>-<1,4> = (<5-1>,<-3-4>)
  6. The answer is <4,-7>
4 0
2 years ago
1. Given the equation ​ ​y​ = -3​x​ + 2.5
valentina_108 [34]

Answer:

a. when x=1 so substitute 1 to any X in the given equation.

y=-3(1)+2.5

y=-3+2.5

y=-0.5

b.when x is -1.5 so substitute -1.5 to any x in the equation

y=-3(-1.5)+2.5

y=-4.5+2.5

y=-2

4 0
3 years ago
Click on all the points that are solutions to y = x^2 - 9.
Oliga [24]

9514 1404 393

Answer:

  B) (2, -5)

  D) (3, 0)

Step-by-step explanation:

I find it convenient to let a graphing calculator plot the points and the graph.

The only two points on the graph of the curve are ...

  (2, -5) and (3, 0)

3 0
3 years ago
M is the midpoint of segment CS. C is at (-8, 2) M is at the origin. What are the coordinates of S?
ahrayia [7]
C(-8,2) and M(0,0) , since M is at the origin. Let x₁ and y₁ be the
coordinates of S →s(x₁ , y₁)

C(-8,2) and S(x₁ , y₁)
The coordinates of M, the midpoint of CS are M(x₂ , y₂)

a) x₂ = (-8 + x₁)/2 , but x₂ = 0, then :
0 = -4+x₁/2 and x₁ = 8

b) y₂ = (2+y₁)/2 , but y₂ = o, then:
0 = 2+ y₁/2  and y₂ = -2

Then the coordinates of  S are S(8 , -2)
4 0
3 years ago
A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute
Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

H_0 : \sigma = 10

H_1 : \sigma \neq 10

The test statistics can be computed as follows:

X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}

X^2 = \dfrac{(36 -1)10.1^2 }{10^2}

X^2 = \dfrac{(35)102.01 }{100}

X^2 = \dfrac{3570.35 }{100}

X^2 =35.704

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703      ( to four decimal places)

Decision Rule : To reject the null hypothesis if  P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.

3 0
3 years ago
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