40 boys and 68 girls
let's start with variables and an equation.
boys: x
girls: 2x - 12
and we know that boys and girls make up the class. so let's add the two expressions.
x + 2x - 12 = 108
3x - 12 = 108
+ 12 + 12
3x = 120
x = 40 boys
BUT x is only the number of BOYS in the class. so we have to find girls now. let's plug in our value of x into the girls' equation.
2x - 12 = # of girls
2(40) -12 = # of girls
80 - 12 = # of girls
68 girls
let's check our answer!
68 + 40 does in fact add to 108, therefore our answer is correct.
Length of the base = 8
Length of the hypotenuse = 17
The length of the third side ''
".
Using Pythagoras theorem, we have
(Perpendicular)² + (Base)² = (Hypotenuse)²
+ (8)² = (17)²
+ 64 = 289
= 289 - 64
= 225
= 
= 
Therefore, the length of the missing side is .
(15)² + (8)² = (17)²
225 + 64 = 289
289 = 289
L.H.S. = R. H. S.
Hence verified.
Answer:
72$
Step-by-step explanation:
8h
h=9
8*9=72$
