Answer:
t = (D/C - 1) (100/r)
Step-by-step explanation:
D = C(1+rt/100)
D/C = 1 + rt/100
D/C - 1 = rt/100
D/C - 1 = t (r/100)
Therfore,
<h2>t = (D/C - 1) / r/100</h2>
Therefore the last option is correct.
<h2><em><u>
PLEASE MARK MY ANSWER AS BRAINLIEST!!!!!</u></em></h2>
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
slope intercept form :
y=m+b
m=slope
If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.
Data:
(8,4)
m=2/3
y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3 (slope intercept form)
Answer: The equation of the line would be: y=2/3 x-4/3.
if we have the next slope "m",then the perendicular slope will be:
m´=-1/m
We have this equation: y=2/3 x+0; the slope is: m=2/3.
The perpendicular slope will be: m`=-1/(2/3)=-3/2
And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:
y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16
answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
Answer:
x
=
4,-4
Step-by-step explanation:
Answer:
The side length is 9m
Step-by-step explanation:
A = 81 m^2
Since the figure is a square, we know the area of a square is A = s^2 where s is the side length
81 m^2 = s^2
Take the square root of each side
sqrt(81 m^2 ) = sqrt( s^2)
9 m = s
The side length is 9m
Answer:
Following are the solution to the given points:
Step-by-step explanation:
Please find the complete question in the attached file.
In this question, we assume that "x" denotes as an actual time of the battery charging, that is a uniform random variable that
In point a:
so, pdf of x =
In point b:
To find

In point c:

In point d:
