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3 years ago

6

The picture frames shown are both squares. The area of the smaller frame is 14 the area of the larger frame. Find the side lengt

h of the larger frame.
The area of the small square is 9in

1 answer:

uranmaximum [27]3 years ago

6 0

the side length of the larger square is 3.5. (14 divided by the number of side, 4)

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In triangle $ABC,$ point $D$ is on $\overline{AC}$ such that $AD = 3CD = 12$. If $\angle ABC = \angle BDA = 90^\circ$, then what

Neporo4naja [7]

Answer:

$BD=4\sqrt{3}\ units$

Step-by-step explanation:

we know that

$AD=12\ units$

$3CD=12$ ----> $CD=4\ units$

see the attached figure to better understand the problem

Triangles ABD and BCD are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

$\frac{BD}{AD}=\frac{CD}{BD}$

substitute the given values

$\frac{BD}{12}=\frac{4}{BD}$

$BD^2=48$

$BD=\sqrt{48}\ units$

simplify

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3 years ago

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erma4kov [3.2K]

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3 years ago

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ad-work [718]

Answer:

$d = 123$

Step-by-step explanation:

The given figure above is an inscribed quadrilateral with all four vertices lying on the given circle, thereby forming chords each.

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This means:

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Subtract 57 from both sides.

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andrey2020 [161]

Answer:

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Step-by-step explanation:

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