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2 years ago

:

Mathematics

1 answer:

NemiM [27]2 years ago

3 0

Answer:

22 hours = hours travelling altogether

Step-by-step explanation:

11 x 2 = 22

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7/4x^2 -2 = - 0.05x + 4

nata0808 [166]

Answer:

$x1=\frac{-2-2\sqrt{29401} }{245} x2=\frac{-2+2\sqrt{29401} }{245}$

Step-by-step explanation:

Step One: Convert

49/16x^2-2=-0.05x+4

Step Two: Multiply Both Sides by 80

245x^2-160=-4x+320

Step Three: Move everything to the left

245x^2+4x-480=0

Final Step: Quadratic Formula

$x1=\frac{-2-2\sqrt{29401} }{245} x2=\frac{-2+2\sqrt{29401} }{245}$

6 0

3 years ago

Four years after opening an account that paid simple interest of 4.25% annually, a depositor withdrew the $2,380 in interest ear

satela [25.4K]

Answer:

Step-by-step explanation:

In order to figure out how much money was left in the account after the interest was withdrawn, we have to first find out how much money was initially deposited to earn that amount of interest! The means to find that initial investment is found in the simple interest formula

prt = I, where

p is the initial investement,

r is the interest rate in decimal form,

t is the time in years, and

I is the interest earned. Notice that we have all those things but the p.

Filling in:

p(.0425)(4) = 2380 and

.17p = 2380 so

p = 14000

That means that 14000 was initially invested. If the depositor withdrew the 2380, then

14000 - 2380 is the amount left in the account, namely, $11620

7 0

2 years ago

Someone please hurry and answer i will mark brainelist!!!!! or how ever you spell it

tigry1 [53]

What is the question?

3 0

2 years ago

What is the row echelon form of this matrix?

USPshnik [31]

The row echelon form of the matrix is presented as follows;

$\begin{bmatrix}1 &-2 &-5 \\ 0& 1 & -7\\ 0&0 &1 \\\end{bmatrix}$

<h3>What is the row echelon form of a matrix?</h3>

The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.

The given matrix is presented as follows;

$\begin{bmatrix}-3 &6 &15 \\ 2& -6 & 4\\ 1&0 &-1 \\\end{bmatrix}$

The conditions of a matrix in the row echelon form are as follows;

There are row having nonzero entries above the zero rows.
The first nonzero entry in a nonzero row is a one.
The location of the leading one in a nonzero row is to the left of the leading one in the next lower rows.

Dividing Row 1 by -3 gives:

$\begin{bmatrix}1 &-2 &-5 \\ 2& -6 & 4\\ 1&0 &-1 \\\end{bmatrix}$