Answer:
Step-by-step explanation:
![\textsf{x=1/2[(4x+5)-50]}](https://tex.z-dn.net/?f=%5Ctextsf%7Bx%3D1%2F2%5B%284x%2B5%29-50%5D%7D)
ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation.
θ is the angle from a standard position of the line OA
The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite
Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent
The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle
θ = 180 - α
sinθ = sin(180-α) = opposite/hypotenuse = 1/√10
cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3
α= arcsin(1/√10) ≈ 18
θ =180 -18 ≈162
When you're out shopping and something you want to buy is on sale. You can take the original price and give it's percentage to find out how much it really is.
-5x + 3x > 22
-2x > 22
x < 22/-2 (greater than sign changes to less than sign when you divide with negative number)
x < -11
Answer:
Step 2 is wrong.
It should be 3x – <u>18</u> + 4x + 12 – 6x
Explanation:
3(x – 6) + (4x + 12) – 6x →
3x – 18 + 4x + 12 – 6x →
(3x + 4x – 6x) + (-18 + 12) →
x – 6
