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ivanzaharov [21]
3 years ago
6

37 is what percent more than 32

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0
86%...think of it like money u could also divide the two
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If tge angle at the center is 62° and the radius is 12 cm.. find the length of arc​
insens350 [35]

Answer:

Step-by-step explanation:

r = 12 cm

Theta = 62

Length of arc = \frac{theta}{360}*(2\pi r)

                      =\frac{62}{360}*2*3.14*12

                      = 12.98 cm

6 0
3 years ago
#26 7s=4 please help
const2013 [10]
7s = 4
/7.    /7 


s= 4/7

thats the equation right?
7 0
3 years ago
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I will give extra points please help
pav-90 [236]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
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Equivalent to 15x + 3?<br> A. 15(1x + 1)<br> B. 5(3x + 1)<br> C. 3(5x + 1)<br> D. 2(15x + 3)
Reika [66]

Answer:

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6 0
2 years ago
In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes
ale4655 [162]

Answer:

The sample mean is \bar{x}=14.371 min.

The sample standard deviation is \sigma = 18.889 min.

Step-by-step explanation:

We have the following data set:

\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

\bar{x} = \frac{{\sum}x}{n}

where, n is the number of values in the data set.

\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }

The mean of a sample is  \bar{x}=14.371.

Create the below table.

Find the sum of numbers in the last column to get.

\sum{\left(x_i - \overline{X}\right)^2} = 6422.0982

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 6422.0982 }{ 19 - 1} } \approx 18.889

7 0
3 years ago
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