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Kobotan [32]
3 years ago
15

85/100 = x/80. What is the unknown quantity?

Mathematics
2 answers:
Natasha2012 [34]3 years ago
7 0

85 x 80 = 6800

6800/100 = 68

x = 68

love history [14]3 years ago
6 0
Cross multiply then flip equation
85 * 80 and x * 100
6800 = 100x 
100x = 6800

Now divide each side by 100
100x ÷ 100 = 6800 ÷ 100
x = 68
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Solve the problem. Use the Central Limit Theorem.The annual precipitation amounts in a certain mountain range are normally distr
bazaltina [42]

Answer:

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 109.0 inches, and a standard deviation of 12 inches.

This means that \mu = 109, \sigma = 12

Sample of 25.

This means that n = 25, s = \frac{12}{\sqrt{25}} = 2.4

What is the probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches?

This is the p-value of Z when X = 112. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{112 - 109}{2.4}

Z = 1.25

Z = 1.25 has a p-value of 0.8944.

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

7 0
3 years ago
What is 10 to the 3 power
GalinKa [24]
Its 10^3 = 1000
10^3 = 10*10*10
6 0
3 years ago
2. What is the relative frequency of a student choosing the aquarium? Give your
Andreyy89

Answer:

What is the relative frequency of a student choosing the aquarium? Give your

answer as a decimal rounded to the nearest hundredth. (The hundreths place is two

decimal places. For example, .9543 would be rounded to .95)

Step-by-step explanation:

5 0
3 years ago
plz help me so i can go to my dads house this weekend plllzzz and do it right and explain how u got it
svp [43]
36 Give me a minute an ill tell you how I got it

6 0
3 years ago
You want to wrap a gift shaped like the regular triangular prism shown. How many
kotegsom [21]

Answer:

697.6 \ in^2

Step-by-step explanation:

-Given the dimensions of the box is 8.7 in, 14 in and 10 in.

Let length=14 in, width=10 in and height =8.7 in

#The surface area of a rectangular prism is calculated as:

Surface \ Area=2(wl+hl+hw)\\\\l=length, w=width, h=height\\\\\therefore Surface \ Area=2(14\times 10+10\times 8.7+14\times 8.7)\\\\=697.6 \ in^2

Hence, the wrapping paper needed has an area of 697.6 \ in^2

8 0
3 years ago
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