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3 years ago

Girl talk????? anything...

Mathematics

2 answers:

omeli [17]3 years ago

5 0

What do you mean by girl talk?

mojhsa [17]3 years ago

4 0

Answer:

IT depends

Step-by-step explanation:

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Write a subtraction problem involving two positive integers with a negative difference. Explain the relationship between the two

Nadusha1986 [10]

Answer:

When both integers have the same value, the difference is zero. The difference between a positive and a negative integer can be positive or negative. When you subtract a negative integer from a positive integer, the difference is always positive this might help

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3 years ago

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The price of an item has been reduced by 5%. The original price was $20. what is the price of the item now?

Makovka662 [10]

Answer:

I think its 19

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2 years ago

Solve the system (x-1)²+(y-2)²=2² and y=2x+2.

Likurg_2 [28]

Answer:

(x, y) = (-0.6, 0.8) or (1, 4)

Step-by-step explanation:

Use the second equation to substitute for y in the first.

(x -1)² +((2x +2) -2)² = 4

x -2x +1 + 4x² = 4 . . . . . . . eliminate parentheses

5x² -2x -3 = 0 . . . . . . . . . . subtract 4, collect terms

Now we can rearrange the middle term to ease factoring by grouping.

(5x² -5x) +(3x -3) = 0

5x(x -1) +3(x -1) = 0

(5x +3)(x -1) = 0

The values of x that make these factors zero are ...

x = -3/5, x = 1

The corresponding values of y are ...

y = 2(-3/5)+2 = 4/5 . . . . for x = -3/5

y = 2(1) +2 = 4 . . . . . . . . for x = 1

The solutions are: (x, y) = (-3/5, 4/5) or (1, 4).

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A graphing calculator verifies these solutions.

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2 years ago

Triangle AOC intersects a circle with center O. side AO is 10 inches and the diameter of the circle is 12 inches. What is the le

zvonat [6]

Answer:

$AC=8inches$

Step-by-step explanation:

It is given that triangle AOC intersects a circle with center O, side AO is 10 inches and the diameter of the circle is 12 inches, thus

OC is the radius of the circle and is equal to $\frac{D}{2}=\frac{12}{2}=6 inches$ .

Now, From ΔAOC, using the Pythagoras theorem, we get

$(OA)^{2}=(OC)^{2}+(AC)^{2}$

⇒ $(10)^{2}=(6)^2+(AC)^2$

⇒ $100=36+(AC)^2$

⇒ $64=(AC)^2$

⇒ $AC=8inches$

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2 years ago

In the △PQR, PQ = 39 in, PR = 17 in, and the altitude PN = 15 in. Find QR.

Licemer1 [7]

Answer:

So, this triangle PQR can be broken into two right triangles, PNQ and PNR, with legs PQ = 39, PN =15, and QN = ? and PR = 17, PN = 15, and NR =? respectively.

Let's solve for what is easier first:

Since we know that 5-15-17 is a Pythagorean triplet, we can infer that NR is 5....like I said earlier, it is a right triangle, so this guess holds true.

Here comes the interesting part:

Now, we have one part of QR, which is QN.

The other part can be solved by using the Pythagorean theorem.

It is (39^2-15^2)^(1/2)..which gives you 36, the square root of 1296, which happens to be the difference between the squares of 15 and 39.

SO, QR = QN + NR

5+36 = 41

QR = 41.

Hope this helps!

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3 years ago

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