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levacccp [35]
3 years ago
6

8th grade math question need an answer asap

Mathematics
2 answers:
timama [110]3 years ago
7 0

im pretty positive its the 3rd one


julsineya [31]3 years ago
4 0

4.9 x 10^8 = 490,000,000

Hope that helps.

--------------------------------------

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Which rate is the best deal for a box of cereal?
kondor19780726 [428]
The answer is c. You find the price per ounce. 4.29/24 = .178 then 3.49/18= .193 then 6.39/39= .163 and 2.49/14 = .177. The cheapest is c. Hope this helps!!!
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3 years ago
Which equation can be used to find 75 percent of 200? HELPNOWW
Karolina [17]

Answer:.75x200

Step-by-step explanation:

4 0
3 years ago
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A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat
DiKsa [7]

Answer:

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let \mu be the random variable that follows a Poisson distribution, then mean \mu = \dfrac{10}{500}= 0.02

and the mean that the random selection of 50 pages will contain no error is \lambda = 50 \times 0.02 =1

∴

Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}

Pr(q =0) = 0.368

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )]    since it is less than 2

P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]

P(X \geq 2) = 1 - [0.3678 +0.3678]

P(X \geq 2) = 1 -0.7356

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

6 0
4 years ago
\root(3)(-3)\root(3)(-5)=\root(3)(15) true or false
Oksi-84 [34.3K]

The equation \sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15} is true

<h3>How to determine the true statement?</h3>

The equation is given as

\sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15}

Apply the law of indices

\sqrt[3]{-3 * -5} = \sqrt[3]{15}

Evaluate the product

\sqrt[3]{15} = \sqrt[3]{15}

Both sides of the equation are the same

Hence, the equation \sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15} is true

Read more about equations at:

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3 0
2 years ago
The solutions of a quadratic equation are 5 and -1. What is the factored form of a related quadratic function?
Alecsey [184]

Answer:

A

Step-by-step explanation:

Given the solutions of a quadratic, say x = a, x = b then the factors are

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Here the solutions are x = 5 and x = - 1, thus the factors are

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f(x) = (x - 5)(x + 1) → A

3 0
4 years ago
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