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WINSTONCH [101]
3 years ago
13

Complete ratio ... i’ll give the brainly thing

Mathematics
1 answer:
Dovator [93]3 years ago
7 0
Whatever the person above said lol
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Solve for x in the equation x^2 + 4x - 4 = 8
erik [133]

Subtracting 8 from both sides of the equation gives

x^2 + 4x - 12 = 0

(x + 6)(x - 2)= 0

x = -6, 2   answer

3 0
3 years ago
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How do you convert 1.063636363... to a fraction?
Sergeeva-Olga [200]
You can do it on a calculator and it gives you 2659/ 2500
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3 years ago
I need to verify identity functions for a one to one function.
Eddi Din [679]

We have the function

f(x)=(x+6)^3

1. For f^-1:

Let y = f(x) = (x+6)^3

Switch x and y to get:

x=(y+6)^3

And solve for y

\begin{gathered} x^{\frac{1}{3}}=y+6 \\ x^{\frac{1}{3}}-6=y+6-6 \\ x^{\frac{1}{3}}-6=y \end{gathered}

And we have y = f^-1(x)

Answer blank 1:

f^{-1}(x)=x^{\frac{1}{3}}-6

2. For f o f^-1 (x):

(f\circ f^{-1})(x)=f(f^{-1}(x))

And solve

\begin{gathered} =f(x^{\frac{1}{3}}-6) \\ =(x^{\frac{1}{3}}-6+6)^3 \\ =(x^{\frac{1}{3}})^3 \\ =x \end{gathered}

answer blank 2

x^{\frac{1}{3}}-6

answer blank 3

x^{\frac{1}{3}}-6

answer blank 4

x^{\frac{1}{3}}

3. For f^-1 o f:

(f^{-1}\circ f)(x)=f^{-1}(f(x))

Solve

\begin{gathered} =f^{-1}((x+6)^3) \\ =\sqrt[3]{(x+6)^3}-6 \\ =x+6-6 \\ =x \end{gathered}

answer blank 5

(x+6)^3

answer blank 6

(x+6)^3

answer blank 7

x+6

4 0
1 year ago
Simplify fully<br> 4x – 8x²<br> 12x-6
Elena L [17]

Answer:

answer of second question 12x-6 =6(2x-1)

Step-by-step explanation:

12x-6

= 6(2x-1) take the common

=Answer=6(2x-1)

5 0
3 years ago
What is the equation of a circle with center at (0, -5) and radius of 7.
timurjin [86]

Answer:

x²+(y-5)²=49

Step-by-step explanation:

3 0
3 years ago
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