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12345 [234]
3 years ago
13

Which answer describes the function f(x)=2x^3-x^2 Odd Even Neither

Mathematics
1 answer:
velikii [3]3 years ago
5 0

it is neither, it cannot be raised to a power unless it is 0 or 1 :)

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Can someone help me with 5-12 asap
Julli [10]

Answer:

Step-by-step explanation:

Replace the variables with the number it is so

5. 3 • 8 - 8 = 16

6. 6 • 1/2 divide by 3 + 9 = 10

7. 8 to the power of 2-12• 1/2 divided by 3 = 62

8. 5 • 3-2 • 3 + 8= 17

9. 824/ 4 = 206

10. 6• 60/ 9 - 22 = 18

11. 16.8/2.4 = 7

12. 9.85 • 4 = 39.5

(“•” mean multiply)

Hope this helped!!

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6 0
3 years ago
What is 6.9 times .27 equal=
nordsb [41]

Answer:

186.3

Step-by-step explanation:

8 0
3 years ago
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I will give brainliest to the person who answers all questions
stellarik [79]

Answer: Hope this helps!

Left to right - Q1 - Q5

1,500, 1,250, 0.25, 105, 25%

Step-by-step explanation:

Q1 - 15,000 * 0.02 * 5 = 1,500

Q2 - 25,000 * 0.01 * 5 = 1,250

Q3 - 20 - ((6 * 1) + (3 * 0.75) + (10 * 0.35) + (4 * 2)) = 0.25, 25 cents

Q4 - 30x + 1,000 = 4,200 (X = 107) Approximately 105 jobs

Q5 - 1,584 / (32 * 66) = 0.75 (75%) 100% - 75% = 25%

4 0
2 years ago
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Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2
butalik [34]

To solve this question, we use the factor theorem, and using it, the polynomial function is:

f(x) = x^3 - 2x^2 - 3x + 6

------------------------------

The factor theorem means that if k is a root of f(x), f(k) = 0.

Thus, applying the factor theorem for this question, we have to choose the function for which: f(2) = 0, f(\sqrt{3}) = 0, f(-\sqrt{3}) = 0

------------------------------

Function 1:

f(x) = x^3 - 2x^2 - 3x + 6

Testing the values:

f(2) = 2^3 - 2(2)^2 - 3(2) + 6 = 8 - 8 - 6 + 6 = 0

f(\sqrt{3}) = \sqrt{3^3} - 2(\sqrt{3})^2 - 3\sqrt{3} + 6 = \sqrt{3^2\times3} - 6 - 3\sqrt{3} + 6 = 3\sqrt{3} - 3\sqrt{3} = 0

f(-\sqrt{3}) = -\sqrt{3^3} - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 = -\sqrt{3^2\times3} - 6 + 3\sqrt{3} + 6 = -3\sqrt{3} + 3\sqrt{3} = 0

Thus, since all three conditions are satisfied, f(x) = x^3 - 2x^2 - 3x + 6 is the polynomial function.

A similar question is given at brainly.com/question/11378552

5 0
3 years ago
Can some one plz help fast F=-m+B/q^3
Pani-rosa [81]

whaaaa

aeeeee

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