If it takes one person 4 hours to paint a room and another person 12 hours to
paint the same room, working together they could paint the room even quicker, it
turns out they would paint the room in 3 hours together. This can be reasoned by
the following logic, if the first person paints the room in 4 hours, she paints 14 of
the room each hour. If the second person takes 12 hours to paint the room, he
paints 1 of the room each hour. So together, each hour they paint 1 + 1 of the 12 4 12
room. Using a common denominator of 12 gives: 3 + 1 = 4 = 1. This means 12 12 12 3
each hour, working together they complete 13 of the room. If 13 is completed each hour, it follows that it will take 3 hours to complete the entire room.
This pattern is used to solve teamwork problems. If the first person does a job in A, a second person does a job in B, and together they can do a job in T (total). We can use the team work equation.
Teamwork Equation: A1 + B1 = T1
Often these problems will involve fractions. Rather than thinking of the first frac-
tion as A1 , it may be better to think of it as the reciprocal of A’s time.
World View Note: When the Egyptians, who were the first to work with frac- tions, wrote fractions, they were all unit fractions (numerator of one). They only used these type of fractions for about 2000 years! Some believe that this cumber- some style of using fractions was used for so long out of tradition, others believe the Egyptians had a way of thinking about and working with fractions that has been completely lost in history.
It is 4170 I believe if my calculations are correct
The reciprocal of 6/5 is D. 5/6
Reciprocal simply means swapping the position of the numbers in the fraction. The numerator becomes the denominator and the denominator becomes the numerator.
We need to get reciprocal of a fraction when division is performed.
For example: 2 ÷ 1/5
2 may be a whole number but in fraction form it is 2/1.
1st fraction = 2/1
2nd fraction = 1/5
In dividing fractions, the 1st step we need to do is to get the reciprocal of the 2nd fraction.
1/5 ⇒ 5/1
Then, we multiply the 1st fraction to the reciprocal of the 2nd fraction.
2/1 * 5/1 = 10
So, 2 ÷ 1/5 = 10
The product of two radicals is equal to the radicand. The square root deletes itself.
So the result is y^3
the answer to this would be C I hope this helps :)
