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stira [4]
2 years ago
10

Question 4 4 pts Lori buys a $1500 certificate of deposit (CD) that earns 6% interest that compounds monthly. How much will the

CD be worth in: 5 years? 10 years? 486 months?
Mathematics
1 answer:
Nady [450]2 years ago
5 0

Answer:

Step-by-step explanation:

5 years

1500(1+\frac{.06}{12})^{12*5}=2023.275229

10 years

1500(1+\frac{.06}{12})^{10*12}=2729.095101

486 months:

1500(1+\frac{.06}{12})^{486}=16935.47074

round those as you please

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Please help due tonight !!!!
gregori [183]

Answer:

okay where is the question

Step-by-step explanation:

follow me on ig dipeshkumar0853822

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4 0
3 years ago
Please answer I will make you brainliest
gtnhenbr [62]

Answer:

3 times as great

Step-by-step explanation:

The most amount of water is 3/4 full

The least amount of water 1/4 full

To get from 1/4 to 3/4, you multiply by 3:

\frac{1}{4}  * \frac{3}{1}  = \frac{3}{4}

(I made 3 into 3/1 to show how you multiply across easier)

7 0
2 years ago
tom has a cube a rectangular prism and a triangular prism. which of the shapes have more than 6 vertices?
Ierofanga [76]

Answer:

<h3>A cube</h3>

Step-by-step explanation:

Vertices of a solid shape is a point where 2 lines or edges of the shape intersects. If tom has a cube a rectangular prism and a triangular prism, then the cube has 8 vertices, a rectangular prism has 5 vertices (a rectangle has 4 vertices plus the point where all the lines coming from the vertices of the rectangle intersects).

Also, a triangular prism has 4 vertices(a triangle has 3 vertices plus the point where all the lines coming from the vertices of the triangle intersects)

Hence the only shape that has more than 6 vertices is a cube.

4 0
3 years ago
Consider the following game, played with three standard six-sided dice. If the player ends with all three dice showing the same
ddd [48]

Answer:

a

 P(A) =  \frac{1}{36}

b

P(B) = \frac{15}{36}

c

P(U) = \frac{11}{36}

Step-by-step explanation:

From the question we are told that

   The  number of dice is  n  =  3

Generally  for all three dice to show the same number the second and the third dice must have the same outcome  as the outcome of the first dice.

This means that the number of outcome the first die can  have is  6  (6 sides), the number of outcome which the second and the third dice can have is  1 (they must match the first )

So the probability that all three dice show the same number on the first roll is mathematically represented as

      P(A) =  \frac{6}{6} * \frac{1}{6} *  \frac{1}{6}

=>   P(A) =  \frac{1}{36}

Generally for two of the three dice show the same number after the first roll then the number of outcome for  one of the  dice would be is  6 , the number of outcome for another one must be   1(i.e it must match the first ) , the number of outcome for the remaining one must be   5 (i.e it can show any of the remaining  5  sides which the first and second dice are not showing )

Now the number of ways of selecting this 2 dice that show the same number from the 3 dice is mathematically represented as

     N  =  ^3C_2

Here C stands for combination

So

      N  =  ^3C_2  = 6

So the probability that exactly two of the three dice show the same number after the first roll is mathematically represented as  

      P(B) = N   \frac{1}{6} *  \frac{5}{6}

=>  P(B) = \frac{15}{36}

Generally from the question we are told that if two dice match, the player re-rolls the die that does not match.

Now the probability that  the die that did not match the first  time will match the second time is

     P(E ) =  \frac{1}{6}

Generally if that one die does not show the same number in the second round , the probability that it will match  in the third round is

    P(R) =  \frac{5}{6} *  \frac{1}{6}

Generally the probability that he wins (i.e when all three are showing the same number ) and  exactly two is showing the same number is mathematically represented as

       P(K) =  P(E)* P(B) + P(R)* P(B)

=>    P(K) =  \frac{1}{6} * \frac{15}{36}  +  \frac{5}{6} *  \frac{1}{6} * \frac{15}{36}

=>  P(K)= \frac{165}{1296}

So the probability that the player wins, conditioned on exactly two of the three dice showing the same number after the first roll is mathematically represented as  

    P(U) =  \frac{\frac{165}{1296}}{\frac{15}{36} }

=>  P(U) = \frac{11}{36}

     

 

6 0
3 years ago
Which equation represents the circle described?
faust18 [17]
ANSWER

{(x - 4)}^{2} +  {(y - 3)}^{2}  =   {2}^{2}

EXPLANATION

The equation of the circle with radius r and centre (a,b) is given by


(x - a)^{2}  +  {(x - b)}^{2}  =  {r}^{2}

The radius is

r = 2

We need to determine the center of the circle from the given equation of another circle, which is,


{x}^{2}  +  {y}^{2}  - 8x - 6y + 24 = 0


We complete the square to obtain,


{x}^{2}  - 8x+  {y}^{2}  - 6y + 24 = 0

{x}^{2}  - 8x+  {y}^{2}  - 6y  =  - 24
{x}^{2}  - 8x+  {( - 4)}^{2} +   {y}^{2}  - 6y  +  {( - 3)}^{2}  =  - 24 +  {( - 3)}^{2} +  {( - 4)}^{2}


{(x - 4)}^{2} +  {(y - 3)}^{2}  =  - 24 +  9+  16




{(x - 4)}^{2} +  {(y - 3)}^{2}  =  1


The centre of this circle is (4,3)


Hence the center of the circle whose equation we want to find is also (4,3).


With this center and radius 2, the required equation is,


{(x - 4)}^{2} +  {(y - 3)}^{2}  =   {2}^{2}


Therefore the correct answer is C.

3 0
3 years ago
Read 2 more answers
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