Given that the time taken to get to campus is inversely proportional to driving rate, let the time be t and rate be r, thus the function will be written as:' t=k/r where k is the constant of proportionality given by: k=tr when r=20 mph, t=1.25 hrs thus k=20×1.25 k=25 miles thus the formula is: t=25/r when r=55 mph, the value of t will be: t=25/55 t=5/11 hours