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shusha [124]
3 years ago
13

What is the standard unit of measurement for mass?

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0
The standard unit is the kilogram.
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Paul and Tom both commute to work. Paul's commute on the train takes 15 minutes more than one third as many minutes as Tom's com
Ronch [10]

Answer:

  45 = (one third)x + 15

Step-by-step explanation:

If x represents the number of minutes Tom commutes, then (1/3)x is "one-third as many minutes as Tom's commute." 15 minutes more than that is ...

  (1/3)x + 15

We are told this is the length of Paul's commute, and that it is 45 minutes. So, the appropriate equation is ...

  45 = (1/3)x +15

8 0
3 years ago
Please help! Urgent!<br> What is the measure of angle B? <br><br> -78°<br> -92°<br> -102°<br> -282°
Step2247 [10]
C i believe because 180 is the overall degree and 50+28=78 and 180-78=102
7 0
3 years ago
Read 2 more answers
Please help me hurry!! 3
marysya [2.9K]

Answer:

It is -1

Step-by-step explanation:

6 0
3 years ago
The function f(x) is shown in this graph.
Sladkaya [172]
The function f(x) goes down by two and over by one:
slope = rise/run = -2/1 = -2.

The slope of f(x) is -2, while the slope of g(x) is -6.

Since -2 is a greater number than -6, the answer is:
C) <span>The slope of f(x) is greater than the slope of g(x). </span>
6 0
4 years ago
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In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a ma
bagirrra123 [75]

Answer:49 sec

Step-by-step explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a)=\frac{v-u}{t}

a=\frac{60\times 60\times 60}{4}

a=54\times 10^3 mi/h^2

To reach a speed of 183.58mi/h with an acceleration of 54\times 10^3 mi/h^2

Using equation of motion

v=u+at

183.58=0+(54\times 10^3)t

t=\frac{183.58}{54\times 10^3}

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

s=ut+\frac{1}{2}at^2

5=0+\frac{1}{2}\times 54\times 10^3 \times t^2

t=0.01360 hour

or t=48.98\approx 49 s

7 0
3 years ago
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